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全部话题 - 话题: 35cl
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l****u
发帖数: 336
1
来自主题: Science版 - Re: 讨论讨论这个问题吧!
C60太复杂了,虽然搞这东西搞了10年:-PP
sigh,好久每接触同位素了,一会还想不出好例子来
以Cl为例,其同位素有35Cl, 37Cl,
35Cl : 37 Cl =3:1 (好象是这样吧:()
先说(aA+bB+cC+dD+…….)^n(上一片给错了),
a, b, c….为同位素比,A, B, C….为元素的同位素
n就是某个peak中,某元素的个数
现在可以说了,如果含有2个chlorine , A = 35Cl, B=37Cl
(3A+1B)^2= 9A^2 + 6AB +B^2,
这样,3个峰高比应该为9:6:1
3个峰的质量数分别为: 2*A=70, A+B=72, 2*B=74
再多推起来就费劲了,自己写个code吧
h********g
发帖数: 143
2
Thank you very much!
Are you talking about the triplet of CDCl3 in C-NMR?
Actually, I don't think it is due to C-CL coupling.
I searched the triplet of CDCl3 in C-NMR and found this:
http://u-of-o-nmr-facility.blogspot.com/2007/09/isotope-shifts-
The CDCl3 signal is a 1:1:1 triplet due to the J coupling to the deuteron
which is a spin I=1 nucleus having three energy levels. The chemical shift
difference between the CHCl3 and CDCl3 isotopomers is called an isotope
shift.
Question 1: Since chlorin... 阅读全帖
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