d***n
发帖数: 993 | 1 我想要的物品:
SouthWest Points @1.2 + fee
单张面值:
可接受的价格(必须明码标价！):
7680 整数倍 up2 4***[email protected] + fee
物品新旧要求:
邮寄方式要求:
买卖双方谁承担邮寄损失(Required if not code only):
付款方式说明:
其他补充说明:
广告的有效期:
until 06/14
物品来源:
我的联系方式:
PM
or SMS/Call 5I7 3O3 OI83
二手交易风险自负！请自行验证是否合法和一手卡！: |
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c****e
发帖数: 9482 | 5 小水葱知道流程吧？ 呵呵
需要先登记入学， 然后网上可以选课， 学费是和一门课多少学分有关系的
btw, 上次给你发的另外的city of Santa Clara的那个链接， 秋季的hip hop课也网上
可以看到了， 从8/22开始注册
周四晚6:30PM - 7:15PM
Hip Hop I, II - 46839
Ages: 18 Yrs. and over
Spots Available: 15
周三晚6:30PM - 7:15PM
Hip Hop III - 46080
Ages: 14 Yrs. and over
Spots Available: 15 |
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P******n
发帖数: 1220 | 6 24*8*30*12 = 69120
24*8*20*12 = 46080
average = 50000
not bad for entry-level MS.
still |
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N***m
发帖数: 4460 | 7 来自主题: Programming版 - 问个问题 对于一个数n，把它因式分解，可以得到一个list，比如
12=2*2*3,list=[2,2,3]。
我现在做个循环
for(int i=0;i<100;i++) {
FactorizerCounter counter = new FactorizerCounter(2000*i+1,2000*(i+1));
...
得到 list in this range;
}
where the above snippet inside the loop obtains a list with maximum length
in the given range (2000*i+1,2000*(i+1)), both inclusive.
我发现因式分解的长度有点涨落，但是变化不大（O(logN)?），
不知道有没有啥简单的解释？
运行结果如下：
===============================
2*2*2*2*2*2*2*2*2*2=1024
2*2*2*2*2*2*2*2*2*2*2=2048
2*2*2*2*2*2*2*2*2*2*2*2=4096
2*2*2*2*2*2*2... 阅读全帖 |
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r****r
发帖数: 29 | 8 Could somebody please send me the "附件: PTnote-temp.doc (28160 字节)
and 附件: history-1.doc (46080 字节)" posted by picasab (麦地 皮) on Wed Jun
18 15:04:30 2008?
You are great! God bless you! I thank you so much! |
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r****r
发帖数: 29 | 9 Thanks, 水晶!
The website you provided is the article. Attached to that article is 2 files
called "附件: PTnote-temp.doc (28160 字节)" and "附件: history-1.doc (
46080 字节)" . What I am looking for is the 2 files which were attached to
that article. You can see their names at the bottom of the article. But
their links are missing. Thanks, again. |
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