x*****p
发帖数: 1707 | 1 Using recursive.
Suppose an array A of integers is given to hold all golden pieces. Its index
is from 0 to N-1.
Let function f(int startIndex, int endIndex) returns the maximum money you
can get.
int f(A, int startIndex, int endIndex) {
int sum = summation from A[startIndex] to A[endIndex];
if (startIndex==endIndex) return A[startIndex];
int choice1 = sum - f(A, startIndex+1, endIndex);
int choice2 = sum - f(A, startIndex, endIndex-1);
return (choice1>choice2?choice1:choice2)... 阅读全帖 |
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M**********e
发帖数: 4237 | 2 上右三 CHOICE3, 下左一choice2，下左二choice1
买到高过级别标识的牛肉是bonus |
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z*******g
发帖数: 416 | 3 because you were blinded by:
1. "qinghua" sticker on his dick
2. meth-background
3. work in a finance firm in chicago.
lesson:
1.if something is too good to be true, it usually is.
2. select a dick by its quality not the sticker it bears
3. prepare to be cheated, or at least disappointed when meeting with a
stranger. |
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r**********9
发帖数: 19633 | 4 medstudent发了这么多帖子可见多么不淡定了
我就是好奇---那个男的说她离异装未婚--这条到底是不是真的呀
如果是真的他两是夜壶对尿盆 |
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p***d
发帖数: 2171 | 5 她的确是离异. 最早发的几个征贴上有这条, 后来可能因为形势所迫, 不提了. |
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z*******g
发帖数: 416 | 6 rongrong i agree with you this time.
let me put this way: if you are a virgin, she is never married. |
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z*******g
发帖数: 416 | 8 How about: if you are not a virgin, she is never married. |
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Y**********n
发帖数: 3853 | 9 哈哈哈， 结果最后你们谁也没找到个清华的，
就俺找到了。 哈哈哈 |
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e*********w
发帖数: 367 | 13 我也支持在UMD或IKEA先集合一次，开尽量少的车去OC。定一个比较合适的出发时间，
如果第一次集合不到的人就到OC找大家。另外就在海边玩玩就可以了，不用去那里
SHOPPING吧，我选CHOICE1(both option 1 and 2)。 |
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