L******t
发帖数: 1985 | 1 You send a plaintext of your choice to receiver, who will send back you the
ciphertext. Then you got the key by plaintext XOR ciphertext.
Proof:
P xor K = C
P xor P xor K = K
==> K = P xor C
The weakness in the scheme is the encryption algorithm is reversible. And
the receiver cannot verify the authenticity of a sender. |
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w*******e
发帖数: 285 | 2 我在server和client之间的传输用AES加密解密，String和byte[]之间的转换都用UTF8
编码
public String decrypt(String CipherText) {
try {
byte[] raw = decoder.decodeBuffer(CipherText);
byte[] stringBytes = decrypt_cipher.doFinal(raw);
String PlainText = new String(stringBytes, "UTF8");
return PlainText;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
public String encrypt(String PlainText) {
try {
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L*********s
发帖数: 3063 | 3 ciphertext only, no encryption algorithm, no sample, 你解个试试 |
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h**********g
发帖数: 3962 | 4 是不是大家讲中文，日文，韩文？白人会不开心。
也许他心里在想：为什么我说话是用plain text，
而你们说话是用ciphertext，而且还使用三种不
同的钥匙？ |
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