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全部话题 - 话题: everyroom
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r******2
发帖数: 67
1
Located at Judge street and Elmhurst Ave, Elmhurst. Elevatored building,
prewar, laundary in basement. 2 blocks to Broadway. close all.
5th floor, fully painted, big kithen with window, Bathroom has a window too,
2 big closets, big room more than 450SF with three windows. move in the
middle of June. Rent does not include electricity and cooking gas.
Need credit check (more than 750) and stable job. No more than 2 people
since it is a studio.
I will be there Saturday afternoon 06/09/07 to show it
n*******2
发帖数: 603
2
来自主题: HouseRental版 - Bedroom for rent, 60st & Lexington ave UES
Bedroom for rent, 60st & Lexington ave UES
small bedroom for rent, with platform bed built-in, in a 2 bed apt.
south facing big windows in everyroom. marble bathroom.
location: 60st and lexington ave, next to bloomingdale
1 block to 59st subway NRW456, and 63 st F train.
rent $1000 + utilities.
my lease ends on May 31, you can take over and renew after that.
contact me by site mail.
s*****n
发帖数: 5488
3
来自主题: JobHunting版 - 两道经典design问题求助
我个人认为,设计题是很open的讨论题,问设计题的单位一般来说要和用户交流。这题
首先考你交流能力。所以,说一千道一万都没有用的。要看面馆的交流。
第二,不理解为什么预订系统里面会有user这个概念。本质上,考预订这种题是考资源
管理方面的设计能力。例如多线程访问。而且可能是web系统,可能是本地系统。所以
,这个user在web到底是个什么?用户注册的账号?
所以,我认为答题是可以从最简单开始,例如房间预订就是概念上对资源(房间)和日
历的一个锁定。然后再问你要考OOD呢,设计模式 singleton呢(只能有一个booking
system, everyroom only one instance too).web系统呢,数据库设计呢,还是用什么
数据结构来存储呢,用什么rw锁还是什么锁呢,还是考虑怎么查询空房呢。
最后,方法一概念上肯定是错的。User 不可能has a room or booking system。
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