ET
发帖数: 10701 | 1 既然叫做pole zero doublets, 自然都是auxuliary amplifer带来的，哈哈。
都是gm3/c3 - gm3 - 是boosting amplifier's , c3 - 是output of boosting amplif
iers.
2nd pole - first no-domiant pole是cascode transistor的source (input amplifie
r's drain),那里是gm2/c2 - c2是这点的caps.
btw, transfer function is H(s) = term1* term2
term1 = gm1/sc2
term2 = (1+s*gm3/c3)/(s^2*A+s*gm3/c3+1)
A =c1c3/(gm2*gm3)
intutively 看不是万能的，至少我没这本事。 画画small signal有些时候还是很有用
的。想你给的这个结构，从boosting amplifier的output断开feedback就行。
但如何intutively interpret的transfer fu |
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s*****n
发帖数: 2 | 2 1) Without feedback, assume the impedance looking up at the source of M3 is
RD, then the impedance looking at the source of M3 is
Rin = (RD+Ro3)/(1+gm3*Ro3) = (RD+Ro3)/(gm3*Ro3)
2) M1 senses the Iout (Iout*RD) and feedback the current to input node gm1*
RD*Iout, loop gain T = gm1*RD
3) shunt feedback at the input --> Rin_eff = (RD+Ro3)/(gm3*Ro3*gm1*RD) (
ignore the 1+T factor)
4) Now look at the RD, 坑爹, depends on the load impedance:from the fig,
assume no loading,
RD = Rdsp || (gmn*Rdsn^2+Rds... 阅读全帖 |
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ET
发帖数: 10701 | 3 这里的一个重要区别是考虑high frequency, capacitive load
要看impedance,而不只是低频下的resistance.然后用 r*c来近似一个pole.
实际上，也可以假设output resistance 很大，无穷来简化。
你是从vin->vout ,在m3 的gate端的断开的吗？
比如你的boosting amplifier，有Gm, smallest Rout & infinite Rin , ideal opamp
.
从vin, 在m1的输出有 v2, v2=gm1*vin/sc1, 可以画一个current source:gm1*vin //
c1
v2控制boosting amplifier & cascode amplifier
boosting amplifier, 可以画成gm3*v2 //c3， 它有输出电压：v4=gm3*v2/sc3
再看cascode transistor, 它的current source是gm2*vgs , here vgs=v4-v2, 这个cu
rrent source // c3
所以，vout= |
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y***k
发帖数: 9459 | 4 我还是往多里算的。一台used gm l32发动机gm dealer报价500块，人工费700块，这才
1200.如果你买white box全新的l32，带gm3 年10万迈保修，也就1200。考虑到楼主的
century用的是比l32这种lesabre上的3.8l低一档次的3.1l l系发动机，只可能更便宜。 |
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e*i
发帖数: 10288 | 5 Forward this post to your email--if you are using telnet
_=_
_=_ Part 001 of 001 of file 5_off_30_cpn.zip
_=_
begin 666 5_off_30_cpn.zip
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M"Q1`O%=`5C_:H$@,^D`;"H4XT(9!0/]L@\'0R`-M*!Z>/]O@4`C\... 阅读全帖 |
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f********e
发帖数: 195 | 6 【 以下文字转载自 EE 讨论区 】
发信人: freetofree (Try&Try), 信区: EE
标 题: Apple RFIC interview
发信站: BBS 未名空间站 (Tue Sep 24 17:03:34 2013, 美东)
Apple RFIC is hiring. I did not get an offer. Here are the interview
questions. Hopefully they are helpful for you.
I'm not sure apple is doing wifi or not. Currently they are using other
companies' chip. But definitely they want to do some work.Maybe for
customized low power
wireless chips
Here's are the questions:
1, How to design an LNA, how to improve linearity? how t... 阅读全帖 |
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a***n
发帖数: 5665 | 7 yes raining very hard here.
mlb is so stupid.... the Sat gm3 should have called off too instead of
starting at almost 10pm.
inning |
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l****o
发帖数: 184 | 8 首先谢谢回答得这么仔细，赞一下学习精神：）
关于transfer function 我是这么推导的，见附图
Gain boosted amplifier在这里的作用就是把gm2提高了(AGE+1)倍
所以在表达式中与普通cascode 不同的地方就是多了一个(AGE(S)+1)
这个+1的部分就create another zero, 但是这个transfer function所表示出来的
Non-dominate poles 分别是the output of the gain boosted amplifier(V2)和node
v1，
这就与另外一个pole需要和zero在一起的假设相矛盾。
我不太明白我这样推倒错在什么地方，我分别看了2002年的一篇tcas 和berkeley的
lecture video,
都有相似的结果。
至于我说把gm3/c3 push到high frequency上面，这个当然要具体问题具体分析，越往
外推越好。
再次感谢帮我解答问题，，：）
amplif
amplifie |
|
f********e
发帖数: 195 | 9 Apple RFIC is hiring. I did not get an offer. Here are the interview
questions. Hopefully they are helpful for you.
I'm not sure apple is doing wifi or not. Currently they are using other
companies' chip. But definitely they want to do some work.Maybe for
customized low power
wireless chips
Here's are the questions:
1, How to design an LNA, how to improve linearity? how to reduce NF?
A: high vov, gm3 cancellation ,feedabck etc. high ft, noise cancellation,
higher current etc.
2, MOS transistor... 阅读全帖 |
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