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全部话题 - 话题: janani
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a*****g
发帖数: 1320
1
来自主题: SanDiego版 - 问一道概率题--谢谢大家 (转载)
【 以下文字转载自 WaterWorld 讨论区 】
发信人: ashuang (越忙越年轻), 信区: WaterWorld
标 题: 问一道概率题--谢谢大家
发信站: BBS 未名空间站 (Tue Feb 21 00:09:18 2012, 美东)
MANU AND JANANI ARE PLAYING A COIN TOSS GAME WITH A FAIR PENNY. MANU GETS
A POINT IF THE PENNY LANDS ON HEADS, AND JANANI GETS A POINT IF THE PENNY
LANDS ON TAILS. THE SCORE IS JANANI 9, MANU 7, IN A GAME TO 10 POINTS. WHAT
IS THE PROBABILITY THAT JANANI WILL WIN THE GAME?
a*****g
发帖数: 1320
2
【 以下文字转载自 WaterWorld 讨论区 】
发信人: ashuang (越忙越年轻), 信区: WaterWorld
标 题: 问一道概率题--谢谢大家
发信站: BBS 未名空间站 (Tue Feb 21 00:09:18 2012, 美东)
MANU AND JANANI ARE PLAYING A COIN TOSS GAME WITH A FAIR PENNY. MANU GETS
A POINT IF THE PENNY LANDS ON HEADS, AND JANANI GETS A POINT IF THE PENNY
LANDS ON TAILS. THE SCORE IS JANANI 9, MANU 7, IN A GAME TO 10 POINTS. WHAT
IS THE PROBABILITY THAT JANANI WILL WIN THE GAME?
a*****g
发帖数: 1320
3
来自主题: WaterWorld版 - 问一道概率题--谢谢大家
MANU AND JANANI ARE PLAYING A COIN TOSS GAME WITH A FAIR PENNY. MANU GETS
A POINT IF THE PENNY LANDS ON HEADS, AND JANANI GETS A POINT IF THE PENNY
LANDS ON TAILS. THE SCORE IS JANANI 9, MANU 7, IN A GAME TO 10 POINTS. WHAT
IS THE PROBABILITY THAT JANANI WILL WIN THE GAME?
p*********y
发帖数: 2741
4
Heads up, Orange County. Saturday, February 8 is the 29th Annual Asian
Pacific American Awareness Conference at UC Irvine. This year's theme is
LOVE, short for "Listen to Our Voices and Empower." The keynote speakers are
Janani Balasubramanian, Beau Sia, and Sumun Pendakur. Here's some more info:
29th Annual Asian Pacific American Awareness Conference
DATE: February 8, 2014
TIME: 9am-530pm
LOCATION: UCI Student Center
KEYNOTE SPEAKERS:
**Beau Sia
**Janani Balasubramanian
**Sumun Pendakur
WORKSHO... 阅读全帖
p*********y
发帖数: 2741
5
【 以下文字转载自 LosAngeles 讨论区 】
发信人: playadelrey (A smile is a curve gets things straight), 信区: LosAngeles
标 题: 29th Annual Asian Pacific American Awareness Conference@ UC Irvine
发信站: BBS 未名空间站 (Sun Jan 19 19:57:19 2014, 美东)
Heads up, Orange County. Saturday, February 8 is the 29th Annual Asian
Pacific American Awareness Conference at UC Irvine. This year's theme is
LOVE, short for "Listen to Our Voices and Empower." The keynote speakers are
Janani Balasubramanian, Beau Sia, and Sumun Pendakur. Here... 阅读全帖
m*****8
发帖数: 127
6
来自主题: ebiz版 - 苹果店小二说没有解锁机
251 Questions on Unlocked iPhones Select type of question. Choosing a
selection will reload the page.
Are iphone 6 without contrac unlocked??
Asked by Gustavo F from Pembroke Pines Sep 9, 2014 Flag as inappropriate (
Are iphone 6 without contrac unlocked??)
Answer now (Are iphone 6 without contrac unlocked??)
11 Answers (Are iphone 6 without contrac unlocked??)
Similar Questions (Are iphone 6 without contrac unlocked??)
Best Answer:
Hi
There is no unlocked iPhone 6. I spoke with apple and tmobil... 阅读全帖
m******3
发帖数: 983
7
FYI Here is 2009 High School Graduate Data
PLANO ISD
Plano Senior High School
(V) Jeremy Ying, 18, of Plano will attend Harvard University and major in
molecular cellular biology.
(S) Shijia (Jessica) Liu, 17, of Plano will attend University of
Pennsylvania and major in business.
Plano East Senior High School
(V) Jananie Ramesh, 18, of Plano will attend University of Texas and major
in business.
(S) Tarang Kapoor, 17, of Plano will attend University of Pennsylvania and
major in economics.
Plano
w*p
发帖数: 16484
8
来自主题: WaterWorld版 - 问一道概率题--谢谢大家
1-Janani赢的概率(=1/2*2*2)
s*********t
发帖数: 4253
9
来自主题: TrustInJesus版 - 十个人像
王志明(1907年-1973年12月29日),中国基督教牧师,云南武定人,苗族。
生平
王志明出生在中国云南省武定县下长冲。云南北部以武定洒普山为中心的地区是中国内
地会的一个重要传教区,信徒以苗族为主。1913年到1924年間,王志明在武定大阱和洒
普山中国内地会为当地苗族人所办的教会学校裡接受教育,毕业后成为教会学校的教员
,从教19个年头。1940年起任滇北地区内地会洒普山总堂传道员,1948年按立为洒普山
总堂牧师,成为当地教会领袖。中华人民共和国成立后,1951年,外国传教士被驱逐出
中国,王志明继续负责当地教会。 他虽然忠于国家,但拒绝参加当地的批斗地主和反
对外国人的活动。
文革开始后,在1969年,包括王志明在内的当地21名基督教领袖因反对信徒参加“三忠
于”活动被逮捕,1973年12月29日,66岁的王志明被中国判处死刑,在当地万人批斗会
上被枪决。
西敏寺教堂
1980年12月1日,王志明得到中国政府的公开平反。
1998年7月9日,英女王宣布20世纪世界十大基督教殉道者,包括波蘭神父聖國柏(St.
Maximilian Kolbe; 1894—1941年)、因信仰... 阅读全帖
h******g
发帖数: 11250
10
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两个硬币,四种可能,头,头;头,字;字,头;字,字
7
假设袋里共有5n个球,则红球有3n个,
取两个红球概率为(3n/5n)*((3n-1)/(5n-1))=3/10,可得n=1
共有5个球,3个红球,2个白球
8
Janani获胜概率等于1-Manu获胜概率
Manu要获胜,必须连续三次都翻到tail,这个概率为1/2*1/2*1/2=1/8
9
6个cube,从1-6,最有可能的情况是1-6每个数字出现一次,所以总和为21
另一种考虑的方法是先考虑2个,这个和可以从2-12,概率分别为
2: 1+1 1/6*1/6=1/36
3: 2+1 1/6*1/6+1/6*1/6=1/18
4: 1+3 3+1 2+2 2*(1/6*1/6)+(1/6*1/6)=1/12
5: 1+4 4+1 2+3 3+2 1/9
6: 1+5 5+1 2+4 4+2 3+3 5/36
7: 1+6 6+1 2+5 5+2 3+4 4+3 1/6
8: 2+6 6+2 3+5 5+3 4+4 5/36
9: 3+6 6+3 4+5 5+4 1/9
10: 4+6 6+4 5+5 1/12
11: 5... 阅读全帖
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