a*e
发帖数: 78 | 1 Advanced Engineering Mathematics by Kreyszig 9th edition
英文硬皮原版，$60
Introduction to Optics by Pedrotti
International edition $20
Principle of Quantum Mechanics by Shankar
国内影印版 $10
Solid state physics by Ashcroft/Mermin
国内影印版 $15
Modern Quantum Mechanics by Sakurai
国内影印版 $10
Optics by Eugnen Hecht
国内影印版 $10
价钱可以商量，有兴趣请站内联系
或者email ： 1*******[email protected] |
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h****8
发帖数: 44 | 2 如果不是给数学系的人上课的话，
个人推荐一本
Introductory Functional Analysis With Applications
Kreyszig 写的，特别适合入门，不需要测度论就可以理解。写的相当好。
John Wiley | ages: 688
另外一本也不错的入门是Maddox的Elements of Functional Analysis
如果给数学系的用，选择会多很多。Rudin的吧，不过不知道会不会太难了。 |
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f******n
发帖数: 176 | 3 Kreyszig is good to read, Rudin or Friedman is hard to read. |
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a*****e
发帖数: 4577 | 4 Advanced engineering mathematics by Erwin Kreyszig
最新版本
Bookstore买的新书
没怎么用过
原价税前120+
打算卖60
有兴趣的可以站内信箱联系 |
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a*e
发帖数: 78 | 5 Advanced Engineering Mathematics by Kreyszig 9th edition
英文硬皮原版，$60
Introduction to Optics by Pedrotti
International edition $20
Principle of Quantum Mechanics by Shankar
国内影印版 $10
Solid state physics by Ashcroft/Mermin
国内影印版 $15
Modern Quantum Mechanics by Sakurai
国内影印版 $10
Optics by Eugnen Hecht
国内影印版 $10
价钱可以商量，有兴趣请站内联系
或者email ： 1*******[email protected] |
|
c*******d
发帖数: 353 | 6 given . as dot product, and x as cross product, we know that
(axb).(cxd) = (a.c)(b.d) - (a.d)(b.c) (1)
also known as identity of lagrange.
How to use the above formula to prove (axb)xc = (a.c)b - (b.c)a (2)?
I know how to prove (2) with kronecker's identities. But what's the
connection between (1) and (2)?
I don't get this from p.14 in 'Differential Geometry' by Kreyszig.
Also, what's the connection between d2x/dt2 and d2x/ds2? Problem 12.2
contradicts with (12.7')
Thanks, |
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c*******d
发帖数: 353 | 7 In the book 'differential geometry' by Kreyszig, a result is frequently used
about the principal curvature k1, k2. For example, we know that gaussian
curvature K=k1*k2.
When lines of curvature (curves with principal curvature as tangents)
coincide with coordinate curves, it can be shown k1 = b_1^1, the first
element of a mixed tensor with degree 2 and 1 covariance indice. (p.131)
The author then equate k1 = b_11/g_11, k2=b_22/g_22. And this result is used
in several places. Here is what I am hav |
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w**a
发帖数: 1024 | 8 看了陈省身 youku 上的
陈省身 微积分。
尤其是41，42，前后的那几讲，他讲了曲面论，用外微分很容易的就把
第一，二，三微分几何的基本形式导出来了。
比
Kreyszig, E. Differential Geometry. New York: Dover, 1991.
里面的简洁很多。 |
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t*****n
发帖数: 225 | 9 Introductory Functional Analysis With Applications by Erwin Kreyszig |
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m*******s
发帖数: 3142 | 10 Erwin Kreyszig的那本似乎不符合你的要求,
要看就看Neumann的那本吧. |
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