y******u
发帖数: 96 | 1 用的话筒是MXL3000 mic bundle，interface是focusrite scarlitte 2i2。
interface的gain 1连接了话筒，打开了interface自带的48Vphantom power，设置按照
软件指导弄了。不过output没有连接任何东西。不知是否有影响。input
configuration选择的是scarlitte2i2，output configuration选择的是built-in
output，不知是否正确。耳机连在电脑上，不过interface上面，所以Output没有选在
interface。
请教大家帮我看一下是否正确。谢谢！ |
|
s******g
发帖数: 15854 | 2 有点想搞个胆机放在客厅里，一边听，一边做装饰，看这个港产的Audio Space AS-3i
我就想知道他能不能推动JBL L830这种音箱
音箱的spec是
Speakers Maximum Output Power: 300 Watts
Speakers Response Bandwidth: 48 - 40000 Hz
胆机的spec是
Input Impedance: > 100Kohm (RCA)
Output Impedance: 4, 8 ohm
Output Power: 32Wx2 Class AB2 P-P (Ultralinear) 16Wx2 Class AB2 P-P (Triode)
Damping Factor: > 5
Frequency Response: 20Hz - 30KHz / -1dB
T.H.D.: < 1% 20Hz-20KHz (Ref. Output)
懂的给号号脉，包子酬谢 |
|
i****o
发帖数: 1183 | 3 Full Spec:
Number of effective pixels: 16.3 million pixels
Image sensor: 23.6mm×15.6mm（APS-C）X-Trans CMOS with primary colorfilter
Sensor Cleaning system: Ultra Sonic Vibration
Storage media: SD memory card / SDHC memory card / SDXC(UHS-I) memory card
File format (still image): “JPEG (Exif Ver 2.3 *2), RAW (RAF format), RAW+
JPEG (Design rule for Camera File system compliant / DPOF-compatible)”
Movie format: H.264（MOV）with Stereo sound
Number of recorded pixels: “L：4896ｘ3264 4896ｘ2760 3264 ×3264... 阅读全帖 |
|
d*****0
发帖数: 68029 | 4 【 以下文字转载自 Faculty 讨论区 】
发信人: MVPYao (退役了), 信区: Faculty
标 题: 原来发学术论文也可以批马甲
发信站: BBS 未名空间站 (Wed Apr 9 19:28:30 2014, 美东)
旷世奇才：无锡江南大学丁锋
作者：马甲哥
关键词：中国百篇最具影响国际学术论文、高引用次数论文、疯狂自引、马
甲、疯狂报奖、低调
一直关注科技评价，近几年一个人名反复出现在各重量级评价体系中，那就
是无锡江南大学“太湖学者”特聘教授，物联网学院（原通信与控制工程学院）
教授丁锋。什么叫“重量级”，2011年中国百篇最具影响国际学术论文，江南大
学有两篇入围，排名全国第8，而这两篇全部来自丁锋。丁锋显然太低调了，因
为实际上当年他共有三篇论文入围，那第三篇文章是他和他的学生WANG DQ（王
冬青）以青岛大学名义入围的。2012年中国百篇最具影响国际学术论文，丁锋再
次入围。
最具国际影响力显然是基于各学科论文引用评出的，那么基于Web of
Science的Essential Science Indicators数据库查询来自于JIANGNAN U... 阅读全帖 |
|
I*********y
发帖数: 185 | 5 Oh, regarding that the output power of an EDFA can never exceed a certain
Pmax. Why is that? I checked the commercial specs of many non-AGC EDFA products,
they do have a parameter called "output saturated power", but its definition is
the output power when the amplifier gain drops to a half of the small signal
gain.It by no means implies that it's the upper bound of the amplifier output
power, according to my understanding.
As a matter of fact, Pout increases when Pin increases, even though gain |
|
s**********i
发帖数: 711 | 6
one of those two (well, three) ways:
1, output the image to a file under web dir, readable to all
and in your CGI, do something like:
print "location: http://myhost.mydomain.com/temp/output001.gif\n\n";
as only output
or, in your CGI, do something in output HTML
 http://myhost.mydomain.com/temp/output001.gif">
2, open the image creating program with pipe in CGI like
open IMAGE, "program |";
in output part, do
print "content-type: image/jpeg\n\n\";
print while ;
you make necessar |
|
z**r
发帖数: 17771 | 7 you sure? I thought the timers should show up in the output of "sho clns
interfa" too, but check the output, there is no hello or dead interval. And
after I change the default hello interval to 50 from the default (10 sec),
it doesn't reflect there either so I got confused. Well it only shows the
decresing
time, I am trying to find an output similar to the "show ip ospf int" output |
|
t********r
发帖数: 853 | 8 Product: 54226196/BSTOCK
AC Adaptor: AC Adaptor
Battery: Internal lithium polymer battery (4000mAh)
Processor: Intel® Core™ i7-2640M processor (2.80GHz / 3.50GHz
with Turbo Boost)
Chipset: Intel HM67
Color: Black
Display: 13.1" LED backlit Full HD display (1920 x 1080)
Finger Print Sensor: Biometric Fingerprint Sensor
Graphics (Video Card): Intel® HD Graphics 3000
Backlit Keyboard: LED Backlit Keyboard
Operating System: Genuine Windows® 7 Pro... 阅读全帖 |
|
|
d******i
发帖数: 7160 | 9 i only want to output HDMI1, not matter it connects to monitor or TV.
what's the scenario i should execute the "xrandr --output HDMI1"?
by connecting to monitor, or to TV?
if to the TV, when it has the output (then no point to run the command),
or lose the output (then WHERE to run the command)?
Thanks.
port |
|
c*****t
发帖数: 1879 | 10 I have to test outputs against standard outputs. My code is a
compiler-compiler (i.e. lex/yacc like).
Even worse, I might have to test the if the outputted java code
which in turn gets compiled produce the right outputs for given
inputs.
One of the reason why I needed to test is because a slight tweak
may not be apparent in correctness, and only through tests to
tell. A single generated piece of code itself can work in some
cases, but not all cases...
I am having a major headache :( ATM, I ca |
|
x****a
发帖数: 1229 | 11 // public void postfix (String input)
// {
// Stack s1 = new Stack();
// String output = "";//to store the postfix expression
//
// for (int i =0; i
// {
// //get the single letter
// char letter = input.charAt(i);
//
// //convert infix to postfix
// if (letter =='1'||letter =='2'|| letter =='3'||letter =='4'||
letter =='5'||letter =='6'||
// letter =='7'||le... 阅读全帖 |
|
m*****k
发帖数: 731 | 12 我在试http://hadoop.apache.org/common/docs/r0.20.2/quickstart.html
我用的是win7 和 cygwin,
Standalone Operation
By default, Hadoop is configured to run in a non-distributed mode, as a
single Java process. This is useful for debugging.
The following example copies the unpacked conf directory to use as input and
then finds and displays every match of the given regular expression. Output
is written to the given output directory.
$ mkdir input
$ cp conf/*.xml input
在这一步
$ bin/hadoop jar hadoop-*-examples.ja... 阅读全帖 |
|
m*****k
发帖数: 731 | 13 我在试http://hadoop.apache.org/common/docs/r0.20.2/quickstart.html
我用的是win7 和 cygwin,
Standalone Operation
By default, Hadoop is configured to run in a non-distributed mode, as a
single Java process. This is useful for debugging.
The following example copies the unpacked conf directory to use as input and
then finds and displays every match of the given regular expression. Output
is written to the given output directory.
$ mkdir input
$ cp conf/*.xml input
在这一步
$ bin/hadoop jar hadoop-*-examples.ja... 阅读全帖 |
|
c*****t
发帖数: 1879 | 14 Basically, I have a program that takes a script and generate an output.
But the test script itself may have setup and clean up script. Say
myprog < test_setup.s > test_setup.output
myprog < test.s > test.output
myprog < test_clean.s > test_clean.output
I would like it to automatically generate reports on mismatches for
each of such test. Sometimes, I have a single set of setup / clean,
but plenty of tests.
Are there any existing testing framework for this? I could write
one myself, but it wou... 阅读全帖 |
|
g*g
发帖数: 6908 | 15 没用alias
看了看这个lessFAQ。奇怪的是我以前都没碰到过。
Why are there problems if my .cshrc, .profile or ENV files produce output?
Like some other programs, less invokes the shell to perform certain
operations, such as expanding special characters in filenames. It does this
by invoking a shell program and reading the program's output. If the shell
itself produces output, this interferes with the output coming from the
program that less is trying to read from. This problem is not unique to less
; for example, if you |
|
y***d
发帖数: 2330 | 16 先用 system->pref->monitors 来试试，不行的话，用 xrandr:
先修改 /etc/X11/xorg.conf
Section "Screen"
Identifier "aticonfig-Screen[0]-0"
Device "aticonfig-Device[0]-0"
DefaultDepth 24
SubSection "Display"
Viewport 0 0
Virtual 3600 1920
Depth 24
EndSubSection
EndSection
重启后，
xrandr --output CRT1 --off;
xrandr --output DFP2 --off;
xrandr --output CRT1 --auto --primary;
xrandr --output DFP2 --auto --right-of CRT1 |
|
g*********s
发帖数: 1782 | 17 手头书不少，几本经典的都有了。但是看来看去还是对STL里的概念很不清楚，觉得这
些描述太抽象。谁能简明扼要地总结一下啊？
比如iterator，我的理解是推广的指针，是指向其他对象的对象。那么指针上的所有操
作iterator都支持吗？另外iterator又被分成input iterator, output iterator等等
。他们和iterator class之间是继承关系吗？input iterator和output iterator号称
只支持一小部分指针操作。另外书上说使用output iterator的算法必须是单遍算法，
这个又是什么意思？
下面这个例子将vs填上5个"hello"。但是为啥要用这个output iterator back_
inserter？直接vs.end()或者vs.last()不行吗？或者直接循环5次push_back。引入这
么细分的算法意义何在呢？
std::vector vs;
std::fill_n(std::back_inserter(vs), 5, "hello"); |
|
j****9
发帖数: 2295 | 18 来自主题: Programming版 - 问个面试题 我是用文字表达test cases的。
Empty Linked list {}, expected output null
Linked list of one element {1}, expected output null
Linked list of five elements {1, 2, 3, 4, 5}, expected output 1
Linked list of more than five elements {1, 2, 3, 4, 5, 6}, expected output 2
需要写成程序? 能帮写一个么？ |
|
t*****n
发帖数: 25 | 19 Program a fast and simple solution to the following problem without using
any
regular expression or pattern matching utilities. Given a non-finite stream
of
characters, output an "A" if the characters "xxx" are found in exactly that
sequence. If the characters "xMx" are found instead, output a "B". Do not
re-
process characters so as to output both an “A” and a “B” when processing
the
same input. For example:
1. The following input xxMxMxxxMxxx would produce the following output: BAA
2. The |
|
g*********s
发帖数: 1782 | 20 #include
#include
int main() {
const int count = 1024*1024*128;
const int buffSz = 1024*128;
FILE* output = fopen("cbuff.dat", "w");
setvbuf(output, NULL, _IONBF, 1024*128);
for (int i = 0; i < count; i++) {
//int x = i;
int buffer[buffSz];
buffer[i%buffSz] = i;
if ((i+1)%(buffSz) == 0)
fwrite(buffer, sizeof(int), buffSz, output);
}
fclose(output);
}
#include
#include
int main() {
co |
|
b*******u
发帖数: 501 | 21 Here is the whole problem.
Write a program that outputs the numbers 1 thru 100 and obeys the following
special rules:
1. Outputs "Strata" whenever the number contains a 2。
2. Outputs "Red" whenever the number contains 2 identical digits.
3. Outputs "Blue" whenever the number two preceding the number you are on
contained a 2.
第三条Rule是什么意思？
What does it means: “the number two preceding the number you are on
contained a 2.”
Thanks. |
|
r*******n
发帖数: 3020 | 22 我按你的思路改了一下,看效果有没有改善, 然后再用pypy试试.
def process_file(input_file, output_file):
pos = 10
valueMap = dict()
cnt = 0
output = []
with open(input_file, 'r') as f:
lines = f.readlines()
for each_line in lines:
vals = each_line.split('\t')
val = vals[pos]
if val == '' or val == 'null':
continue
else:
if val not in valueMap:
valueMap[val] = len(valueMap) + 1
... 阅读全帖 |
|
r*******n
发帖数: 3020 | 23 我按你的思路改了一下,看效果有没有改善, 然后再用pypy试试.
def process_file(input_file, output_file):
pos = 10
valueMap = dict()
cnt = 0
output = []
with open(input_file, 'r') as f:
lines = f.readlines()
for each_line in lines:
vals = each_line.split('\t')
val = vals[pos]
if val == '' or val == 'null':
continue
else:
if val not in valueMap:
valueMap[val] = len(valueMap) + 1
... 阅读全帖 |
|
E*******F
发帖数: 2165 | 24 这段code运行时为什么会有segmentation fault？
用的是nachos（一个模拟操作系统的教学软件）
#include "syscall.h"
#include "stdlib.h"
#define OUTPUT_LOOP_LIMIT 500
/*
* Set this up to experiment with different nice values. Negative
* values can cause unexpected execution orders. Figuring out WHY
* is an excellent exercise for the student.
*/
#define A_NICE 0
#define B_NICE 5
#define C_NICE 10
#define D_NICE 15
int
main()
{
int a,b,c,d;
int pid;
Echo ("Starting...\n", 12);
/* Divorce the test processes from the m... 阅读全帖 |
|
k****0
发帖数: 7 | 25 challenge accepted!
python, complexity O(N)
def reorder(input_str):
case_queue = list()
letter_stack = list()
output = list()
for i in input_str:
if i in (" ", "."):
while letter_stack:
case = case_queue.pop(0)
letter = letter_stack.pop()
output.append(letter.upper() if case else letter.lower())
output.append(i)
else:
case_queue.append(1 if i.isupper() else 0)
letter_st... 阅读全帖 |
|
s****h
发帖数: 3979 | 26 【 以下文字转载自 DataSciences 讨论区 】
发信人: squash (南瓜之夭夭), 信区: DataSciences
标 题: question about using Hive parameter
发信站: BBS 未名空间站 (Fri Oct 17 15:20:07 2014, 美东)
question about Hive parameter
Support we have some parameters as:
set nyear = '2014';
set nmonth = '10';
set nday = '17';
We generate a new parameter as:
set newdatestring = concat('/foldername/', ${hiveconf:nyear}, '/', ${
hiveconf:nmonth}, '/', ${hiveconf:nday},'/');
Comparing 2 queries
q1:
select ${hiveconf:newdatestring};
q1 output:
/folde... 阅读全帖 |
|
z****e
发帖数: 54598 | 27 激动啥，我已经从学校回来了
弄了一个16vcpu，32g的instance
然后我们爆了3000个threads
用另外20个instances，每个是10vcpu，每个instance爆15个threads
每个thread控制一个unit，互相射
然后把hp调高，这样短时间内不会射死对方，同时用随机数降低活动频率
如果不控制，电脑计算飞快，很快就会发送一堆请求，人脑没那么灵活
.1秒能发送一个命令就不错了
最后并没有出现什么延迟的问题
server side跟我预想的一样，因为不需要处理图像和ai
所以复杂度大幅降低，33ms的主循环可以搞定
绝大多数时间在处理网络的io上，广播时候用async做点处理
这样循环就不会被打断，真正的主线程处理逻辑操作需要时间其实很少
33ms没啥问题，当然复杂度越高，能支持的并发数也就越少
你可以说我们做的游戏复杂度偏低
但是我不认为网游server需要多高的复杂度，哪怕是3d建模，也不会有多复杂
x，y，z三个维度，没啥难的，你非要做复杂来，那没办法
我搞定鸟，下次把这个写在我们的项目说明上
你不信就算了，我对这个话题已经没啥兴趣了
你就是嘴巴上... 阅读全帖 |
|
s****y
发帖数: 503 | 28 我用websphere v9beta（支持JAX-RS 2.0）实现restful，下面这段代码
@GET
@Path("/getJson1")
@Produces(MediaType.APPLICATION_JSON)
public JSONObject getJSON1() {
String input = "This is input";
String output = "This is output";
JSONObject outputJsonObj = new JSONObject();
outputJsonObj.put("input", input);
outputJsonObj.put("output", output);
return outputJsonObj;
}
如果用import com.ibm.json.java.JSONObject实现JsonObject是运行正常的，但是如
果用import org.json.JSONObject来实现就会报如下的错
[ERROR ] Problem with wri... 阅读全帖 |
|
R*****d
发帖数: 420 | 29 一个较难的python输出函数运行信息的project.
有一个 web service,类似这样
#!/usr/bin/env python
import web
import xml.etree.ElementTree as ET
tree = ET.parse('user_data.xml')
root = tree.getroot()
urls = (
'/users', 'list_users',
'/users/(.*)', 'get_user'
)
app = web.application(urls, globals())
class list_users:
def GET(self):
output = 'users:[';
for child in root:
print 'child', child.tag, child.attrib
output += str(child.attrib) + ','
output += ']';
... 阅读全帖 |
|
|
w***g
发帖数: 5958 | 31 我觉得这个就是模拟人的行为.
input, forget, output都是行为, 所以都由state + observation决定.
下一个state由 input * observation + (1-forget) * 上一个state决定.
还是说得过去的.
input和forget是要决定当前state的, 所以不能去掉.
但是output看似可以由当前state决定. 但因为input = 0时其实input没有
进入当前state. 如果没有input直连output有些情况会不能模拟.
举个例子:
你骂我一句, 或者扇我一巴掌, 我都会无脑骂回去(输出).
但是你如果只是骂我一句没到input阈值, 我不会记仇(change state).
你如果删我一巴掌, 我就会记仇. 记了仇我不但骂回去, 还回
以后找机会黑你. 如果没有input直连output, 就做不到你骂我
一句我也立刻骂回去.
你说的也有理. 如果cell内部足够庞大足够flexible, 这种连接
应该自己就能train出来, 最多差一个clock cycle. 不需要人指定
得这么细致. 差得那个... 阅读全帖 |
|
m********5
发帖数: 17667 | 32 why you use iss.eof()?
The common way to do this is directly check after iss>>temp, because their
can be fail, bad, whitespace, or eof. If either fail/bad signal is True, the
temp is not valid.
###
void test(){
string s = "A B C "; // output is A B C C
// If string s = "A B C", then the output would be A B C
istringstream iss(s);
string temp;
int _i = 0;
while (!iss.eof())
{
cout << _i << " iss stat[good,bad,fail,eof]: [" << iss.good() << iss
.bad() <阅读全帖 |
|
s*****t
发帖数: 14 | 33 解决了
FUNCTION {article}
{ output.bibitem
format.authors "author" output.check
author format.key output
new.block
%format.title "title" output.check
不知道这局被谁comment了 去掉%就好了 |
|
i*o
发帖数: 149 | 34 To build a shared object( .so file),I used following commond:
gcc -fPIC -shared -o output.so input.c
and foo( ) is a function defined in input.c
In order to call foo, I did following in calling process:
void * handle = dlopen("output.so",RTLD_LAZY);
if((error=dlerror())!=NULL){
fputs(error,stderr);
exit(1);
}
foo = dlsym(handle,"foo");
foo()...
However, I got result:
./output.so: undefined symbol: foo
I am pretty sure the problem is from the shared object output.so which was not |
|
c*****t
发帖数: 1879 | 35 Makefile is a good tool as well:
INPUT=$(wildcard *.input)
OUTPUT=$(INPUT:.input=.output)
%.output: %.input
@a $< $@
all: $(OUTPUT) |
|
l****q
发帖数: 767 | 36 Thank you so much!!!
But as for #5. The book (B2-47, 2007 edition)says, The average total cost (
ATC) curve is U-shaped. At low levels of output average total costs are high
because average fixed costs are high. As output increases, average fixed
costs fall and thus average total costs fall. However, as output continues
to increase marginal costs and average costs start to increase causing
average total costs to rise.
So, I'm confused why average cost falls as output expands under a natual
monop |
|
v**********m
发帖数: 5516 | 37 http://m.f1000research.com/articles/3-291/v1
波士顿地区的千老联合会的报告，文章提到的问题非常典型和深刻，该文已经在圈内得
到了包括大佬们的极大肯定(恐惧)。
OPINION ARTICLE
Shaping the Future of Research: a perspective from junior scientists[v1;
ref status: approved 1, approved with reservations 1,http://f1000r.es/4ug]
Gary S. McDowell1*, Kearney T. W. Gunsalus2*, Drew C. MacKellar3, Sarah A.
Mazzilli4, Vaibhav P. Pai1, Patricia R. Goodwin5, Erica M. Walsh6, Avi
Robinson-Mosher7, Thomas A. Bowman8, James Kraemer9, Marcella L. Erb10, Eldi
Schoenfeld1... 阅读全帖 |
|
l****q
发帖数: 767 | 38 got some some help in Accounting club, but still confused regarding #5.
Her explaination is:
Average cost falls as output expands. This is the reason that there is a
natural monopoly, since the average cost decrease as output increase.
But the book (Becker CPA B2-47, 2007 edition)says, The average total cost (
ATC) curve is U-shaped. At low levels of output average total costs are high
because average fixed costs are high. As output increases, average fixed
costs fall and thus average total cost |
|
b****i
发帖数: 619 | 39 是找关系的，有个如下系统：
input: 12; output: 6
input: 6; output: 3
input: 14; output:8
现在问，input=22的时候，output是多少？
另，这属于哪一类问题呢？一般思路又是怎样？
预谢 |
|
l********r
发帖数: 175 | 40 I checked the fftw-2.1.5 and decided to install it again. I used "make
clean" to clean the files I built before. Then did following:
>./configure. by piping the output and reading the output
,it is ok
> make piping and reading the output
carefully, it is also ok.
> make install I changed myself into superuser first, and
piped the output to log.make_install file, which looks ok. but on the
screen, it showed me following |
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l****q
发帖数: 767 | 41 got some some help in Accounting club, but still confused regarding #5.
Her explaination is:
Average cost falls as output expands. This is the reason that there is a
natural monopoly, since the average cost decrease as output increase.
But the book (Becker CPA B2-47, 2007 edition)says, The average total cost (
ATC) curve is U-shaped. At low levels of output average total costs are high
because average fixed costs are high. As output increases, average fixed
costs fall and thus average total cost |
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w*****1
发帖数: 473 | 42 【 以下文字转载自 Statistics 讨论区 】
发信人: wz99331 (dotti), 信区: Statistics
标 题: a question about SAS
发信站: BBS 未名空间站 (Mon Apr 2 12:52:18 2012, 美东)
我需要用MACRO 语言，用DO LOOP 改变一个模版的５个固定参数创建一些新的DATA，检
测这些新的DATA最大似然值.下面是我的CODE， 但是不能运行，大家能否帮我看看?包子
酬谢！
data parents; set csgl.individs;
keep i QTP pedid dgeno;
if i <=2;
run;
/* Do loops for grid search */
/*Y=g+R(mixed model), where g=Major Gene(latent fixed effect)with 3
values: mudaa, mudab, mudbb and R = Residual(variance component)*/
/*the max, min, and std w... 阅读全帖 |
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g*******r
发帖数: 140 | 43 I did not calculate the relationship accurately. But it should not be
difficult. During phase1, output is solely discharged by load; During phase2
, output is charging by inductor, output will be increased until inductor
current is lower than loading current. You could calculate the output
voltage drop in phase1 plus that in phase2..
For choosing L&C, I suggest you find some typical products matching to your
design, and follow their L&C configuration.
the |
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j***u
发帖数: 26 | 44 我作了一个low pass filter, 我用一个PMOS作bias current, PMOS differential
input pair和NMOS active load作出一个简单的one stage amplifier，然后把ouput接
到negative input端,unity negative feedback,就形成了一个voltage follower。然
后我在output端和gnd间接了一个capacitor.模拟结果给出了output的dc average 和
input dc average有大概10mV的电压差。
可是我同时用NMOS differential pair和PMOS active load作了一个相对应的filter，
模拟结果显示这个output和input的dc average几乎相等，实际测量出的dc offset也得
有10mV多，说明transistor model应该是比较ideal的。
所以使我困惑的是，那个PMOS input pair的filter，为啥模拟结果就已经有10mV的dc
offset了呢？如果output |
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r*********i
发帖数: 67 | 45 1. you are sort of right. However, 14.204 = 3.644 + 0.099 + 10.461.
Image that there is some logic first, then a register(FlipFlop), then the
output pad. 3.644 is the delay of the logic in front. Then the delay in the
FF (from d to q you know) is 0.099. Then 10.461 is the time from the
register output to the output pad. All other numbers are just the breakdown
of the three numbers. 3.644 is not the clock tree delay. All these are
relative to the clock at the input. You should not worry about cl... 阅读全帖 |
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h********t
发帖数: 555 | 46 Assuming the poles of the OpAmp and 1/(Cload*Rd) are located at high
frequency, then 3db bandwidth of the circuit you are showing is determined
by R and C of the node vx.
if you ignore cp, (assume cp is 0), the output resistance looking into vx is
1/((1+A)*gm). Capacitance load is C2. pole = 1/RC=(1+A)gm/C2
Note: if we ignore Cp, the equivalent load capacitance to Vx is C2 only. The
reason is simple. if you apply at test current source at vx, the current
won't go to C1, because it is assumed ... 阅读全帖 |
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t*********r
发帖数: 845 | 47 在这个版再贴一次吧。
最近刚刚面了Apple HID group 的 sensor and algorithm组的algorithm engineer,
没有成功。记述一下面试经过，并给自己发广告求内推。
大致经过：
5月底网投。6月底recruiter电话联系。七月初hiring manager电面，就问了问简历
。接着发了三道题，让3天内做完。交上作业后，安排两周后onsite。onsite 9：30开
始，一直到4点。不包括最后的recruiter,共面了7个人，都是白板做题。一周后收到据
信。
onsite详述：
(1) Hiring manager.简单客套之后做题。(a) 两个单频信号，频率相同，如何计算
phase difference; (b)手机通话中，microphone如何cancel speaker sound;
(2) hardware engineer.先问了我做过的一个项目，然后做题。如何用rc电路设计
一个low-pass filter.如果input signal is u(t), what is the output.filter
stability... 阅读全帖 |
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r*****1
发帖数: 805 | 48 My CCS protocol:
P.S.：多有重复，谨防遗漏，仅供参考。
Screening test: General—Lipid profile/ multi-vitamin; Elderly—DEXA scan&
Calcium& VitD/ Colonscopy or FOBT/ vaccination; F-- >18yo Pap smear; >50yo
Mammogram; reproductive age- folate; menopause- Lipid/DEXA/FOBT; M-- >50yo
PSA; sickle cell dz child-prophylaxis w penicillin till 5yo, CF-prophylaxis
w Abx
Prophylaxis: Pantoprazole, pneumatic compression stocking;
Acute abd w perforation: triple Abx- Gentamycin/ Ampicillin/
Metronidazole (口诀：阿扁举旗庆国庆)
E... 阅读全帖 |
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