|
L******k
发帖数: 33825 | 2 好的 理解了！！
谢谢了啊~~
我就是一直在纠结 RHS！！ |
|
W*******Q
发帖数: 275 | 3 在美国industrial zone 不能与 residential zones 混合的。看下图大概知道上下班堵
车原因了。大家每天在高峰时刻在两个区内奔波。
Santa Clara Country zoning maps
https://www.sccgov.org/sites/dpd/DocsForms/Documents/Zoning_Atlas.pdf
注意：黄色是
R1 (single family residential)
R2 (duplex family residential)
RHS （residential high density)
阳谷不幸介于果果与狗狗之间。085 & 089 离工业区最近。
拜果果30年发展之托，cupertino/SJ West/Saratoga 都是既得利益者。
这10多年狗狗崛起，把山景城房价带动起来。
阳谷本来没中国超市，无有名大公司。自己过自己小日子。
可最近8年狗狗，果果，领英大发展。果果也在造宇宙飞船。所以都来阳谷以北工业区
借地发展。SMS就搬来不少flg码公。
如果以Stanford U + PA为中心，MV+MP+woo... 阅读全帖 |
|
|
c****u
发帖数: 8308 | 5 我觉得就是cuttonwood lake那边晃过去的. richardson high 和 utd 还跑过coyote呢
. RHS那个是wfaa直升机直播, 几个animal precint和pd的在下面拿网套. utd 那个是
亲眼看见了...夜里10点多在waterview上, 从itt tech compound 晃进 phase 2 |
|
y**s
发帖数: 376 | 6 Angies List top 3 inspectors
#1: Reliable Home Services Inc (RHS Inspections, Inc.
www.rhsinspections.com
70 reviews A
#2: Inspections By Bob
www.inspectionsbybob.com
61 reviews A
#3: THE BUILDING INSPECTOR OF AMERICA
www.gethomeinspector.com
42 reviews A |
|
|
|
|
b*****o
发帖数: 332 | 10 LOL.. my brain fart big time.. |
|
|
|
b*****o
发帖数: 332 | 13 why not? add 4g on frame for more power and stability.
很少下网，下网的都是eyes not on the ball， human error, 裸拍也出界，就那水平
，不出界才怪了，但感觉拍子力量绝对是涨了，更容易出界了。
不懂为啥butt cap加重就会严重降低拍子力量？ 除非静重增加导致拍头速度下降很多
？不过这1oz我感觉对RHS似乎也没那么大的影响吧。 |
|
h******n
发帖数: 734 | 14 恩 会的 这种general conditioning 没坏处.
racket head speed(rhs) comes most from the rotation of the arm on both the
shoulder ane elbow joint.
但是你必须要能prestetch你的internal rotators in the shoulder.
leg push就是干这个事的，
黑岛虽然嘴上说不用腿，但其实还是有很多的leg push 否则没法发球。牛顿第三定律。
leg pusｈ 跟最后脚离地多高不是一回事. |
|
|
|
|
b***n
发帖数: 89 | 18 tree staking 的讲究很多，原则上来说：
1. 小树不用 stake，比较大一点，有被风吹松吹倒的危险的树才需要 stake
2. stake 一般要先打进地里，然后再把树种上
3. 光脚树用 single stake，穿鞋树用 double stake ，固定点不能高于树干从下往上
的 1/3 处
4. staking 最多三年就要去掉，能早就早
可以参考 https://www.rhs.org.uk/advice/profile?PID=208 |
|
|
o****n
发帖数: 599 | 20 【 以下文字转载自 Parenting 讨论区 】
发信人: oldgun (麻沸散人), 信区: Parenting
标 题: 请教几个小学数学题。
发信站: BBS 未名空间站 (Tue Aug 9 13:25:37 2016, 美东)
娃看不懂，我看了半天也没搞明白。不知道是题出得太粗糙还是我的英语太差，拿到这
里求教一下。
1.There are 13 groups of birds. The birds laid 72 eggs in all. How many eggs
did each bird lay?
2. Roosevelt & OB combined for 49 points in the championship game. RHS won
by scoring 28points. How many points did OB score?
多谢啊。 |
|
|
|
H********g
发帖数: 43926 | 23 google Roosevelt RHS
About 664,000 results (1.05 seconds)
Search Results
Roosevelt High School: Home
一种可能性 |
|
F*********u
发帖数: 12190 | 24 数学上RHS不是right-hand side么 |
|
|
c*****t
发帖数: 1879 | 26 This is a long post...
I am trying to update CookCC (a lexer / parser generator in Java) for
a new feature.
One existing CookCC feature is that one can specify the lexer pattern
and parser grammar in Java annotations. For example:
@CookCCOption
class MyParser extends GeneratedParser
{
@Lex (pattern = "[_A-Za-z][_A-Za-z0-9]*", state = "INITIAL")
String scanIdentifier ()
{
return yyText ();
}
@Rules (rules = {
@Rule (lhs = "Expr", rhs = "Expr '+' Expr"),
|
|
g*****n
发帖数: 56 | 27 from effective C++ (2nd ed) item 28
struct widgets{
class widget {....};
static const Widget operator+(const Widget& lsh, const Widget& rhs);
....
};
I am wondering why declare a overloaded operator static? |
|
N***m
发帖数: 4460 | 28 I only change test.h to the following. It passed the compilation. But I do
not
know why?
test.h
=============================
#include
class index_object_1_comparator;
class index_object_2_comparator;
class index_object_2;
class index_object_2_comparator {
public:
bool operator() (const index_object_2 & lhs, const index_object_2 & rhs)
const;
};
class index_object_1 {
private:
double index;
std::set::iterator iter;
public:
index_ob |
|
t*********s
发帖数: 5 | 29 it depends on what can show up in the quotation marks,
for example:
Media description="for example, '1' + '1' = '2';"
Is the above valid in your applications??
*** if no [,;=] in the quoted stuff, then it might be:
(?!\s)([^=,]+)=(["']?)([^,;]+)\2
check on $1(attr) and $3(value) for the attr-value pairs.
*** If on the other hand, you can have any graphic chars
enclosed in the RHS quotation marks, then
(?!\s)([^=,]+)=(?:(["'])(.+?)\2|(\S+))
check on $1 for attrs and the concatenation of
$3 a |
|
h********l
发帖数: 67 | 30 是不是说，类成员函数可以访问同类的object中私有变量？
const Triangular_iterator& rhs |
|
P********e
发帖数: 2610 | 31 where did you get this code?
For templates, place all the non-inline member function definition in the .h
file. This seems contrary to ordinary, but for templates, those member
function will not be compiled and will be waiting for run-time type define.
I don't know if this will help, but at least, you can get something right.
rhs); |
|
X****r
发帖数: 3557 | 32 bool operator== ( const char* lhs, const string& rhs ); |
|
X****r
发帖数: 3557 | 33 前一句 a=a+5+c;就应该出错了。你的operator +返回的是const X&，
而operator +自己的*this不是const，所以operator +的结果不能再
调用operator +。你把operator +改为
const X& operator+(const X& rhs) const;
const X& operator+(int m) const;
就对了。 |
|
b********r
发帖数: 1080 | 34
我的理解是a=a+5+c先执行a+5, 返回的是const&, 也就是a本身.但这个const a
的operator + 在做+c 时企图改变*this的值,所以不对.
我觉得应该改成
X& operator+(const X& rhs);
X& operator+(const int m);
才对.就是去掉前后的const. |
|
z****e
发帖数: 2024 | 35 返回值：
1.return by value
2.return by reference
3.return by const reference
我不知道理解的对不对，
2,比1高效对吧？
3,就是为了不改2对吧？
那么这个帖子里的程序，是3.而你给的方法是1.
1,比3,效率低对吧？
那为什么不用3？ |
|
z****e
发帖数: 2024 | 36 通过你的解释，你一句话，我豁然开朗。这个设计我想明白了。多谢了。
但是我现在觉得返回常量引用更好。
不知道你同意不同意？ |
|
t****t
发帖数: 6806 | 37 看上去你明白了, 实际上你没明白.
you should return a new object when you should.
See Effective C++, Item 21 (3rd Edition): Don't try to return a reference
when you must return an object.
I am sure Meyer explains much better than me. |
|
z****e
发帖数: 2024 | 38 sure i must read it.
谨遵。 |
|
|
h******6
发帖数: 5 | 40 下面的这段代码为什么会出错？ 谢谢！
#include
#include
class Stack{
public:
Stack();
~Stack(){delete[] _buffer;}
private:
const int _capacity;
int _size;
int *_buffer;
Stack & operator = (const Stack& rhs );
};
Stack::Stack():_capacity(10), _size(0){
_buffer = new int[_capacity];
}
int main(){
std::vector stackArray(3);
} |
|
g*********s
发帖数: 1782 | 41 i see. now i think i understand the code.
the int() operator is defined such that in "cout << s", s is implicitly
converted to an int to output.
s = for_each(v.begin(), v.end(), s) is an assignment that calls the
default assignment operator. we can actually just keep the RHS.
one remaining doubt: what if the class Sum has another float() type
converter defined? in that case which one would cout pick up? |
|
t****t
发帖数: 6806 | 42
no, if you just keep RHS, then the result is lost.
std::for_each send in the functor by value (and return by value, of course).
so the accumulated value is kept in a local copy of functor inside for_each.
this functor is returned and copied again. just like a=a+1, you can write
a+1 (that's a valid expression), but the result is lost. |
|
s*w
发帖数: 729 | 43 1) need default constructor for foo
2) 看不懂， const X& operator+(const X&rhs) const; 这个返回 reference 指向谁
啊？总不能是 this， const function 不让改 this
3) 看不懂， 不是普通的 template specialization 吗？ |
|
t****t
发帖数: 6806 | 44 yes, you can. but use @ to indicate slices, and use repetition operation to
repeat RHS (this is not like matlab, where scalars are automatically
expanded to match vector/matrix size)
@arr[(1..3, 4, 8)] = (5) x 5; |
|
c**********e
发帖数: 2007 | 45 copy constructor 为什么用const reference. 我解释关于为什么用reference是 对的
，对于为什么用const，我的解释是 prevent the constructor from modifying the
object being copied. tnnd他说不对
A::A(const A& rhs) {...}
What does the const mean?
Somebody claims "The question is what const means here? I think it means
that one is prohibited to change the constant reference passed in. In
contrast, I do not think it means that one must pass in a reference of a
constant object to call the copy constructor."
Is he right or wrong? Thanks. |
|
k*******3
发帖数: 1909 | 46 下面程序copy来自C++ essential 4.7节，
Triangular_iterator begin() const
{ return Triangular_iterator( _beg_pos ); }
请问
return Triangular_iterator( _beg_pos ); 这句话的语法是怎么样的？
Triangular_iterator是自定义的一个class吧，class后面直接加（_beg_pos)什么意思
呢？
如果是返回一个Triangular_iterator的object, 不需要定义成
Triangular_iterator obj(_beg_pos）；
return obj；吗？
谢谢！
================================Full Class definition==================
class Triangular_iterator
{
public:
Triangular_iterator( int index ) : _index( index-1 ){} //*... 阅读全帖 |
|
G*****7
发帖数: 1759 | 47 i thought the boobilicious rhs ad banner (Scarlet Johnson?) already rendered
mitbbs nsfw... |
|
y**b
发帖数: 10166 | 48 以前读C++ Primer第四版中文版给自己写了个摘录，一搜索“初始化”，发现内容还很
庞杂，贴出来供参考，前面是页号。
042 两种初始化: 直接初始化(), 拷贝初始化=
044 变量初始化：类类型调用默认构造函数，局部内置类型不初始化，全局内置类型初
始化为零。
080 容器元素的值初始化(未指定元素的初始化式时)：类类型调用默认构造函数，内置
类型置零。
097 数组元素的初始化(同变量初始化规则044)：元素为类类型的数组调用默认构造函数
；局部内置数组不初始化，全局内置数组初始化为零。
117 new动态数组元素的初始化：类类型调用默认构造函数，内置类型不初始化，或指定
进行值初始化为零(且只能为零)。
151 new动态对象之初始化：类类型调用默认构造函数，内置类型不初始化，或指定进行
值初始化为任意值。
对提供了默认构造函数的类类型，没有必要进行值初始化, 会自动调用构造函数：
string *p=new string;和string *p=new string();无区别。
对内置类型或未定义默认构造函数的类类型，存在区别：int *p=new int... 阅读全帖 |
|
m********r
发帖数: 334 | 49 class example {
public:
example(string str){
cout <<"ctor with string "<
example() {
cout<<"ctor without string" <
example( example& rhs){
cout<<"copy ctor "<
};
int main (int argc, char* argv[])
{
string str = "123456789";
example e1(str);
example e2 = str;
example e3 = e1;
example e4 = example();
return 0;
}
这个例子来自C++Primer，在VS2010可以编译，gcc下e2 and e4报错：no matching
function for call to example::example(example)
如果在copy constr... 阅读全帖 |
|
