p***e
发帖数: 29053 | 1 【 以下文字转载自 PhotoForum 讨论区 】
发信人: poise (majia#1: Photogears), 信区: PhotoForum
标 题: xmax，摔坏了个灯架
发信站: BBS 未名空间站 (Wed Dec 26 10:26:52 2012, 美东)
闪光灯摔了2次 |
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f*****i
发帖数: 143 | 2 找到四个中最大数Xmax，按照n=1 到 N 分成不同等分，再把其它的数去除
Xmax / n得到+/-余数， 统计+/-(余数/Xmax*n)平方和，最后找到平方和最小的方案n.
N就是允许出现比例的最大值，比如10或者15。再大就没有意思了。 |
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h***o
发帖数: 539 | 3 BBS水木清华站∶精华区
发信人: FangQ (奥萨马·本·拉登), 信区: MathTools
标 题: Mathematica函数及使用方法--绘图函数
发信站: BBS 水木清华站 (Sat Nov 28 21:50:37 1998)
Mathematica函数及使用方法--绘图函数
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十四、绘图函数
二维作图
Plot[f,{x,xmin,xmax}] 一维函数f[x]在区间[xmin,xmax]上的函数曲线
Plot[{f1,f2..},{x,xmin,xmax}] 在一张图上画几条曲线
ListPlot[{y1,y2,..}] 绘出由离散点对(n,yn)组成的图
ListPlot[{{x1,y1},{x2,y2},..}] 绘出由离散点对(xn,yn)组成的图
ParametricPlot[{fx,fy},{t,tmin,tmax}] 由参 |
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l*********8
发帖数: 4642 | 4 A 2-D bounding box can represented as (Xmin, Xmax, Ymin, Ymax). We have a
set of bounding boxes. There is no intersection between any two of the
bounding boxes.
Now we want to insert one bounding box into the bounding boxes set and merge
the intersected bounding boxes if necessary. Two intersected boxes can be
merged into a big box like this:
Xmin = min(Xmin1, Xmin2); Xmax = max(Xmax1, Xmax2);
Ymin = min(Ymin1, Ymin2); Ymax = max(Ymax1, Ymax2);
Design an algorithm to do t... 阅读全帖 |
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d********g
发帖数: 10550 | 5 能用15张
你可以先到Sears local店去买GC，用GC付钱（同样也是15张限制，所以最大面值是$25
*15=$375）。小地方一般都可以，我上次把Sears所有连锁店的卡拿去，并了1个小时搞
定。第二天就买了接近2k的大件，如果不并卡的话就亏大了
Sears每年圣诞前有Xmax Club GC卡卖，买了囤到11月中旬之后，里面剩余面值自动增
加3%。你可以用GC买点Xmax Club GC，囤几个月更划算。当然你要是像我这样急着买东
西就没有办法囤了 |
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k**********g
发帖数: 989 | 7 If it is given beyond doubt that C is a point on the line extension of AB,
then C is outside the finite segment AB iff
C is outside the axis-aligned bounding box
the cartesian product with
( all x in (xmin, xmax) ) and
( all y in (ymin, ymax) )
where xmin = min ( A_x , B_x )
xmax = max ( A_x , B_x )
etc etc.
for 3D, 4D etc just apply cartesian product over all dimensions.
Upon thinking about that, it seems that even if you apply a unitary
coordinate transform (unitary rotation and/or mirroring) ... 阅读全帖 |
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k**********g
发帖数: 989 | 8 If it is given beyond doubt that C is a point on the line extension of AB,
then C is outside the finite segment AB iff
C is outside the axis-aligned bounding box
the cartesian product with
( all x in (xmin, xmax) ) and
( all y in (ymin, ymax) )
where xmin = min ( A_x , B_x )
xmax = max ( A_x , B_x )
etc etc.
for 3D, 4D etc just apply cartesian product over all dimensions.
Upon thinking about that, it seems that even if you apply a unitary
coordinate transform (unitary rotation and/or mirroring) ... 阅读全帖 |
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x*y
发帖数: 364 | 9 When I make a movie by matlab, how can I define the axis aspect ratio?
When I use axis equal, the ratio is good but the axis range is changing in
each frame;
when I use axis([xmin xmax ymin ymax zmin zmax]), the axis range is fixed in
each frame but the aspect ratio is not right. I want the axis aspect ratio be
(xmax-xmin):(ymax-ymin):(zmax-zmin), can anyone please tell me how to get
this?
Thanks a lot! |
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d***n
发帖数: 412 | 10 Hi,
In my matlab code I need to calculate a three-dimensional integration. I used
triplequad(fun,xmin,xmax,ymin,ymax,zmin,zmax). (xmin,xmax,ymin,ymax) are
specifice by exact values, but (zmin,zmax) are going to be the function of x
, and y. I run the following code where only v1, v2, h are variable in
integral other other symples are pre-defined constants. However, I got error
information provided below. Could somebody help me out? Thanks,
F=@(v2, v1,h)(1-(0.5*exp(-0.717*(-(h-2.5+y*(1/v2-1/v1)) |
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h***o
发帖数: 539 | 11 BBS水木清华站∶精华区
发信人: FangQ (奥萨马·本·拉登), 信区: MathTools
标 题: Mathematica函数及使用方法
发信站: BBS 水木清华站 (Fri Nov 20 21:39:10 1998)
Mathematica函数及使用方法
—————————————————————————————————————
八、数值函数
N[expr] 表达式的机器精度近似值
N[expr, n] 表达式的n位近似值，n为任意正整数
NSolve[lhs==rhs, var] 求方程数值解
NSolve[eqn, var, n] 求方程数值解，结果精度到n位
NDSolve[eqns, y, {x, xmin, xmax}]微分方程数值解
NDSolve[eqns, {y1,y2,...}, {x, xmin, xmax}]
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w*****s
发帖数: 4116 | 14 veri easy a
Buy gift card, buy games(xbox) during Xmax, buy US mint, buy cosmetics, 25k
is very easy. 250k is hard.
都9 |
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w*****s
发帖数: 4116 | 15 excuse me, it is not 'himself'. should be 'herself'. Everyone know it except
you.
I will not loose money at all. Shippin is only $5 difference if ship in West
.
I have PS 20% off and ebizship discount. PS3 can only get $255 after all
fees+shipping. I will not buy here is only make $15 as profit.
All nurse sell to you have to store them till Xmax, hehe
Next |
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w********m
发帖数: 24 | 16 12/24 - 12/27, enjoy ３ nights stay at luxury ocean front Seapointe resort. 1bedroom
suite with full kitchen. Close to beach, shopping and Legoland. Enjoy your Christmas at San Diego.
Asking $300 negotiable (the cheapest on expedia.com is $179/night + tax and
sold out for Xmax)
I will book the hotel for you in your name.
Hotel information:
http://www.carlsbadseapointe.com/default.aspx |
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b******g
发帖数: 2965 | 17 MARY XMAX
病，3个礼拜了，没收到货也不知医生。 |
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d*********1
发帖数: 443 | 18 你可能还没到哭的时候，我们是快熬不住了，这年头当房东是太难呀，一个多月了，无
数人见过，也好几几个人说要“明天来签”， 就是到要签单的人也找不到。现在天天
想着每天50刀没了，平时那么省也挡不住这个呀。 付着两份额mortgage,晚上睡觉也难
安稳呀，Thanksgiving 没过好，现在祈祷 Xmax 前能租出去也，也能过个节。 |
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x********e
发帖数: 35261 | 19 之前有人说平面几何太低级，那就用解析几何表示。
以直角三角形斜边为x轴，直角三角形中点为原点，所有满足条件的直角三角形顶点(x,
y)满足：x^2+y^2=(3/2)^2
直角三角形顶点不超过大正方形边界：x≤1
直角三角形面积：S=3/2*x
直角三角形最大面积：Smax=3/2 when xmax=1
直角三角形顶点位置：y^2=9/4-1=5/4, y=±sqrt(5/4) 所以是(1,sqrt(5/4))和(1，-
sqrt(5/4)) |
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P******e
发帖数: 344 | 21 Any family is interested in sharing a week vacation rental in Either
FlagStaff Nordic Center Or Arizona Snowbowl During the Christmas Holidays (
25-31). |
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c**p
发帖数: 1443 | 22 For Xmax and new year, not to my knowledge. |
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M*******c
发帖数: 4371 | 23 No water here. How sad! |
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M*******c
发帖数: 4371 | 26 SHUTDOWN is coming.
GOING DOWN TO SOMEWHERE WARM?
DRINK CHAMPEIGN at LUNCH, DRINK BEER in the afternoon |
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k*********h
发帖数: 1841 | 27 我有住west Alabama & Shepherd那块的朋友，他说去年Xmax的时候，他一条街上大概
有7、8家都收到了一个陌生人的贺卡。里面夹了一张100刀的gift card，然后是送卡人
的联系方式：希望如果这些人家有意卖房的话，可以首先联系他。
不过四月的成交量已经比三月低了，而且油公司第一个Q的效益都一般般，感觉这股风
走不了多久。 |
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r*****u
发帖数: 169 | 28 仔细地读了一下，是不是因为“蛋疼”两个字？小沈以后注意，有话说话，不要往裆下
走，如果想发泄，多用其它器官，“胃疼”，“肝疼”什么的。
USTA level这个东西，其实没什么好争的，USTA网站上都有，年年更新，有信心就向上
挣吧，没兴趣就在自己的level里面打。
我自己的感觉是如果想上4.0然后hold得住，并往4.5走，需要很好的fundamental。如
果打street tennis出来的，可以3.5所向无敌，pump up到4.0满盘皆输。
用点扯远了，大家merry xmax and happy new year. |
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a********l
发帖数: 39524 | 35 you just took all the life and childhood out of it. paddy wants to kill you. |
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M**X
发帖数: 3014 | 36
赞！靠近大师又近了一大步了~
~闪光灯为什么会摔? |
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p***e
发帖数: 29053 | 37 老婆骂我，买便宜架子。。。。。
已经摔坏了2个灯泡了
◆ Sent from OneTap MITBBS Reader for Windows Phone
[发表自未名空间手机版 - m.mitbbs.com] |
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p***e
发帖数: 29053 | 43 no idea, she was moving....... |
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D***D
发帖数: 176 | 45 没6D好。 换了吧。 ：） 第一张35mm 还是 标头拍的？感觉镜头离得比较近。 |
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p***e
发帖数: 29053 | 46 85mm whithout flash for this first one
40mm with flashes for the 2nd one |
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p***e
发帖数: 29053 | 48 btw, it was hot, and I turned on the fan to cool us lol |
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D***D
发帖数: 176 | 49 瞎评一下
第一张很赞。只是那个玩具颜色太浅了点。 左下角比较亮。 一来有点distraction,
二来感觉左面比右面轻。另外背景里的一左一右两快黑色是电脑屏幕吧？ 同理建议修
掉。
第二张俩娃互动表情很好。所谓telling story.建议crop 成半身像。去掉沙发的颜色
，老二左边的玩具，老大的深色裤子。 |
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