z*y
发帖数: 1311 | 1 Nyquist关于maximum data rate的theorem
< 2 * H * n
where H is the bandwidth of noiseless channel
n is the number of bits for each signal
由于 data rate = baud * n
所以他只是给出了 baud 的上限, baud < 2 * H
至于 maximum data rate, 好像没有啊，n 不是可以随意的么？
It sounds stupid. But I want to know. | m*****n
发帖数: 171 | 2 n怎么能是随意的。n是根据signal的性质确定的，你的signal确定了之后n就确定了啊！
【在 z*y 的大作中提到】
: Nyquist关于maximum data rate的theorem
: < 2 * H * n
: where H is the bandwidth of noiseless channel
: n is the number of bits for each signal
: 由于 data rate = baud * n
: 所以他只是给出了 baud 的上限, baud < 2 * H
: 至于 maximum data rate, 好像没有啊，n 不是可以随意的么？
: It sounds stupid. But I want to know.
| z*y
发帖数: 1311 | 3 yeah, n is only related to signal not medium
所以，只知道bandwidth是不能确定maximum data rate, right?
I can achieve as large data rate as I want by choosing different signals,
right? |
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