d*********g 发帖数: 59 | 1 看到网上有说7次的,8次的,9次的。我觉得最少8次最多9次,不知道答案到底是什么
?谢谢 | s******5 发帖数: 673 | | d*********g 发帖数: 59 | | d*********g 发帖数: 59 | | c******n 发帖数: 11 | | l********y 发帖数: 1327 | 6 请问min 7时怎么得到的?那不是前3名的答案吗? | c******n 发帖数: 11 | 7 a) 5 races to find the 5 1st horses;
b) 1 race to find the fastest;
c) group the 4 horses which raced with the fastest horse in a) with 2nd
place in b).
If the 2nd place one is the slowest in c), no more race is needed. so 7. I
think it's the best case to find top 5. | j********x 发帖数: 2330 | | h*******0 发帖数: 68 | 9 为什么这样就得到第二第三了? 在这种情况下, 也许第三是另一组的第二呢.
【在 c******n 的大作中提到】![](/moin_static193/solenoid/img/up.png) : a) 5 races to find the 5 1st horses; : b) 1 race to find the fastest; : c) group the 4 horses which raced with the fastest horse in a) with 2nd : place in b). : If the 2nd place one is the slowest in c), no more race is needed. so 7. I : think it's the best case to find top 5.
| l********y 发帖数: 1327 | 10 正确的是啥?
【在 j********x 的大作中提到】![](/moin_static193/solenoid/img/up.png) : 这个是错误的
| c******n 发帖数: 11 | 11 错哪了?请指教。
【在 j********x 的大作中提到】![](/moin_static193/solenoid/img/up.png) : 这个是错误的
| b*****e 发帖数: 474 | 12 正确的是 (25 找前 3):
a) 5 races (group A, B, C, D, E) to find the 5 1st horses;
b) 1 race among A1, B1, C1, D1, E1. Assuming the outcome is
A1 > B1 > C1 > D1 > E1
c) race A2, A3, B1, B2, C1,
A1 & top 2 of race c) is the answer | a*******n 发帖数: 56 | 13 最好的情况是7次吧 就是A组的马全部比B1快
最差的情况应该是10次 最后5次每一次只能确定一个名次 |
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