i*c
发帖数: 1132 | 1 如果class A is abstract, class B is not a derived class of A.
下面的code可以运行吗？
A* pa=new B(); |
b********n
发帖数: 609 | 2 of course not
【在 i*c 的大作中提到】
: 如果class A is abstract, class B is not a derived class of A.
: 下面的code可以运行吗？
: A* pa=new B();
|
i*c
发帖数: 1132 | 3 如果A和B都derive from C， 有可能吗？
【在 b********n 的大作中提到】
: of course not
|
r*******y
发帖数: 290 | 4 no
【在 i*c 的大作中提到】
: 如果A和B都derive from C， 有可能吗？
|
N**s
发帖数: 837 | 5 if 'new' is overloaded, maybe
if '=' is overloaded, maybe
【在 i*c 的大作中提到】
: 如果class A is abstract, class B is not a derived class of A.
: 下面的code可以运行吗？
: A* pa=new B();
|
X****r
发帖数: 3557 | 6 No, no.
The new operator and operator new are different. Overloading the latter won't
change the return type of the former.
operator = is not even part of function lookup here. This is a declarator
with an initializer.
【在 N**s 的大作中提到】
: if 'new' is overloaded, maybe
: if '=' is overloaded, maybe
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