i**p
发帖数: 902 | 1 They are accessible in the 1st inheritence, but not in 2nd (see error in the
following code). What reason made C++ designed this way?
class Base
{
protected:
int pro_stat;
public:
int pub_stat;
};
class Default_Der1 : Base
{
int Der1GetProStat() { return pro_stat; } <- Ok
int Der1GetPubStat() { return pub_stat; } <- Ok
};
class Default_Der2 : Default_Der1
{
int Der2GetProStat() { return pro_stat; } <- Error
int Der2GetPubStat() { return pub_stat; } <- Error
}; |
b********n
发帖数: 609 | 2 因为你private inherite了Base，那么Base的东西对Der1来说是可以access的，但对De
r2来说他们就是Der1的private的东东。
the
【在 i**p 的大作中提到】
: They are accessible in the 1st inheritence, but not in 2nd (see error in the
: following code). What reason made C++ designed this way?
: class Base
: {
: protected:
: int pro_stat;
: public:
: int pub_stat;
: };
: class Default_Der1 : Base
|
i**p
发帖数: 902 | 3 It seems what you said is logically. However in Java, the compiler won’t
let you decrease the access of a member during inheritance.
De
【在 b********n 的大作中提到】
: 因为你private inherite了Base，那么Base的东西对Der1来说是可以access的，但对De
: r2来说他们就是Der1的private的东东。
:
: the
|
