b***k
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JackSheng (重新振作) 于 (Fri Jun 19 02:34:20 2009, 美东) 提到:
this one is pretty standard, from another i-bank
which one is larger, e^\pi or \pi^e?
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pcasnik (pcasnik) 于 (Fri Jun 19 10:38:42 2009, 美东) 提到:
for x>0, ln(x)/x gets its maximum at x=e.
hence ln(e)/e > ln(pi)/pi, i.e., e^pi > pi^e.
or use e^x>1+x, and take x=pi/e-1.
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JackSheng (重新振作) 于 (Fri Jun 19 20:34:18 2009, 美东 |
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