r****y
发帖数: 1437 | 1
我想这道题要是没解析解那么思路该如下
做代换，凑成积分函数
f(t) = g(t)/(1-t^2), where t is from -1 to +1
Then
f(t) \= summation(g(ei)w(ei))
where ei is the root for Chebychev polynomials,
for n-order Chebychev,
ei = cos((pi/2)(2i+1)/(n+1)), where i = 0, 1, 2, ...n
嘿嘿纯粹学数值分析学多了根本不想解析解的结果． |
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