S*********g
发帖数: 5298 | 1 (1/n Sum[Sin[m*Pi/50],{m,1,n}])/.n->Infinity
Out[1]=0 | S*********g
发帖数: 5298 | 2 Well, try this, you will find out the answer
Sum[Sin[m*Pi/50],{m,1,n}]/.n->Infinity
Limit[Sum[Sin[m*Pi/50],{m,1,n}],n->Infinity]
The reason why the Limit function gives no anwser is
the summation result of sin is still some sin. And, the limit
for sin is kind of ambiguous stuff if you consider it separately.
/. just set the n to infinity without check the limit.
You can see that the summation is some bounded value for n->Infinity
while it should be zero, in fact.
When it is devided by n-> infini |
|
