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g*******t 发帖数: 124 | 1 The following SAS program is submitted:
data work.empsalary;
set work.people (in = inemp)
work.money (in = insal);
if insal and inemp;
run;
The SAS data set WORK.PEOPLE has 5 observations, and the data set WORK.MONEY
has 7 observations.
How many observations will the data set WORK.EMPSALARY contain?
A. 0
B. 5
C. 7
D. 12
=>The answer is A, I ran SAS and it is A. I don't understand. For concanetin
g data, isn't everything in the combined data file? Why isn't it 12? | l***a 发帖数: 12410 | 2 it's stacking.
MONEY
【在 g*******t 的大作中提到】 : The following SAS program is submitted: : data work.empsalary; : set work.people (in = inemp) : work.money (in = insal); : if insal and inemp; : run; : The SAS data set WORK.PEOPLE has 5 observations, and the data set WORK.MONEY : has 7 observations. : How many observations will the data set WORK.EMPSALARY contain? : A. 0
| g*******t 发帖数: 124 | 3 what does that mean?
【在 l***a 的大作中提到】 : it's stacking. : : MONEY
| g*******y 发帖数: 380 | 4 stacking就是concatenate的意思.
注意里面用的是set,不是merge.
【在 g*******t 的大作中提到】 : what does that mean?
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