x***x
发帖数: 3401 | 1 I have a matrix M and a array L. L contains a list of integers.
The integers are the indexes of the row numbers in the matrix M.
I want to make a new matrix N where the ith row corresponds to the L[i]th
row of the M matrix.
Is there an easy way of doing this?
I can only think of a loop with rbind() function. Any other simpler ideas or
functions?
Thanks | x***x
发帖数: 3401 | 2 举个例子好懂一点
比如L=(3,5,2,7)
那么我需要取M的3, 5, 2, 7行作为N的1, 2, 3, 4行.
谢谢 | m****r
发帖数: 237 | 3 Just use
N=M[L,]
I think that will do it
【在 x***x 的大作中提到】
: 举个例子好懂一点
: 比如L=(3,5,2,7)
: 那么我需要取M的3, 5, 2, 7行作为N的1, 2, 3, 4行.
: 谢谢
| m****r
发帖数: 237 | 4 and r u sure L is an array instead of vector??
or
【在 x***x 的大作中提到】
: I have a matrix M and a array L. L contains a list of integers.
: The integers are the indexes of the row numbers in the matrix M.
: I want to make a new matrix N where the ith row corresponds to the L[i]th
: row of the M matrix.
: Is there an easy way of doing this?
: I can only think of a loop with rbind() function. Any other simpler ideas or
: functions?
: Thanks
| x***x
发帖数: 3401 | 5 oh, right, Thanks!
【在 m****r 的大作中提到】
: Just use
: N=M[L,]
: I think that will do it
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