l******9
发帖数: 579 | 1 I have two functions
m1 = f1(w, s)
m2 = f2(w, s)
f1() and f2() are all blackboxs. Given w and s, I can get m1 and m2.
Now, I need to design or find a function g, such that
m2' = g(m1)
Also, the difference between m2 and m2' must be minimized.
The w and s are all stochastic process.
How can I find such a function g()? What knowledge domain does this belong
to ?
Any help would be appreciated ! | v*******e
发帖数: 11604 | 2 打印个scatter plot, m2 vs m1；就差不多知道了。看起来像线性关系就做线性回归，
想别的关系就再说。 | l******9
发帖数: 579 | 3 m1 and m2 have no obvious linear relationships !
Any help would be appreciated !
【在 v*******e 的大作中提到】
: 打印个scatter plot, m2 vs m1；就差不多知道了。看起来像线性关系就做线性回归，
: 想别的关系就再说。
| c********h
发帖数: 330 | 4 nonparametric methods for arbitrary relationship might be helpful.
Try smoothing splines on y = m2, x = m1, though it may be overkill~ | c*****l
发帖数: 1493 | 5 这问题和f1f2完全没关系，
正如楼上所说，就是个regression。
定义你的distance，找对应的projection matrix。
【在 l******9 的大作中提到】
: I have two functions
: m1 = f1(w, s)
: m2 = f2(w, s)
: f1() and f2() are all blackboxs. Given w and s, I can get m1 and m2.
: Now, I need to design or find a function g, such that
: m2' = g(m1)
: Also, the difference between m2 and m2' must be minimized.
: The w and s are all stochastic process.
: How can I find such a function g()? What knowledge domain does this belong
: to ?
| c***z
发帖数: 6348 | 6 m2' = g(m1)
solving ODE numerically?
not an expert but you can find help at math board
【在 l******9 的大作中提到】
: I have two functions
: m1 = f1(w, s)
: m2 = f2(w, s)
: f1() and f2() are all blackboxs. Given w and s, I can get m1 and m2.
: Now, I need to design or find a function g, such that
: m2' = g(m1)
: Also, the difference between m2 and m2' must be minimized.
: The w and s are all stochastic process.
: How can I find such a function g()? What knowledge domain does this belong
: to ?
| c********h
发帖数: 330 | 7 我猜楼主的那个'不是求导的意思？
【在 c***z 的大作中提到】
: m2' = g(m1)
: solving ODE numerically?
: not an expert but you can find help at math board
| l******9
发帖数: 579 | 8 @catforfish, You are right.
Any help would be appreciated.
【在 c********h 的大作中提到】
: 我猜楼主的那个'不是求导的意思？
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