b******2
发帖数: 13 | 1 A between-Subject psychology experiment: distant tie vs. close tie. The
close tie condition is further broken down into "brother" and "son." My
ultimate goal is to test tie---M---DV mediation. So seems I should pool "
brother" and "son" into one "close tie" condition, but pooling test(i.e.,
chow test) is significant meaning that they can not be pooled together using
raw data values. This is because "brother" and "son" differ significantly
regarding the DV. So, seems using residuals as the new DV is the only option
, right? If so, could you check if my plan is correct? Thank you soooo much!
Step 1. Include only close tie cases(i.e., son cases + brother cases). Use
the son/brother independent variable (possible value: "son" coded as 1, and
"brother" coded as 0). DV is the original DV, sth related with product
choice. Save "standarized residuals."
Step 2. Include ALL cases. Compute the standarized value of the original DV.
Retain the standardized values for "distant tie" cases and discard those
for "close tie" cases.
Step 3. Combine "standarized residuals" generated at step 1. and "
standarized value" of distant cases at step 2. into one new variable. Use
this new variable as the new DV in analyses that include all cases.
Or, there is a procedure for this in some software package instead of me
computing all the residuals & standardized values? I use SPSS, though I
guess the type of software doesnt matter in this case. Thank you! | b******2
发帖数: 13 | 2 P.S. I do not have other licensed software apart from SPSS. | b******2
发帖数: 13 | 3 P.S. I feel my 3-step procedure inappropriately shrinks the difference
between the distant tie condition and the other two conditions... |
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