c*****p
发帖数: 51 | 1 When I combine below first three data steps into one single data step at the
bottom, it generates different results. Can anybody figure out why? Thank
you very much.
data A;
merge X(in=a) Y(in=b);
by key_id;
if a=1;
run;
data A;
set A;
if year<=2006 then id=new_id;
run;
data A;
set A;
drop new_id;
run;
data A(drop = new_id);
merge X(in=a) Y(in=b);
by key_id;
if a=1;
if year<=2006 then id=new_id;
run; |
g****8
发帖数: 2828 | 2 你把 drop放最后试试。
the
【在 c*****p 的大作中提到】
: When I combine below first three data steps into one single data step at the
: bottom, it generates different results. Can anybody figure out why? Thank
: you very much.
: data A;
: merge X(in=a) Y(in=b);
: by key_id;
: if a=1;
: run;
: data A;
: set A;
|
o****o
发帖数: 8077 | 3 这两个判断语句换个次序
if a=1;
if year<=2006 then id=new_id;
the
【在 c*****p 的大作中提到】
: When I combine below first three data steps into one single data step at the
: bottom, it generates different results. Can anybody figure out why? Thank
: you very much.
: data A;
: merge X(in=a) Y(in=b);
: by key_id;
: if a=1;
: run;
: data A;
: set A;
|
