i*o
发帖数: 149 | 1 To build a shared object( .so file),I used following commond:
gcc -fPIC -shared -o output.so input.c
and foo( ) is a function defined in input.c
In order to call foo, I did following in calling process:
void * handle = dlopen("output.so",RTLD_LAZY);
if((error=dlerror())!=NULL){
fputs(error,stderr);
exit(1);
}
foo = dlsym(handle,"foo");
foo()...
However, I got result:
./output.so: undefined symbol: foo
I am pretty sure the problem is from the shared object output.so which was not | m*******m
发帖数: 182 | 2 Maybe you want to use gnu libtool.
【在 i*o 的大作中提到】
: To build a shared object( .so file),I used following commond:
: gcc -fPIC -shared -o output.so input.c
: and foo( ) is a function defined in input.c
: In order to call foo, I did following in calling process:
: void * handle = dlopen("output.so",RTLD_LAZY);
: if((error=dlerror())!=NULL){
: fputs(error,stderr);
: exit(1);
: }
: foo = dlsym(handle,"foo");
| T********r
发帖数: 6210 | 3 try this way:
gcc -fPIC -shared -o output.so input.c -ldl -lc
【在 i*o 的大作中提到】
: To build a shared object( .so file),I used following commond:
: gcc -fPIC -shared -o output.so input.c
: and foo( ) is a function defined in input.c
: In order to call foo, I did following in calling process:
: void * handle = dlopen("output.so",RTLD_LAZY);
: if((error=dlerror())!=NULL){
: fputs(error,stderr);
: exit(1);
: }
: foo = dlsym(handle,"foo");
| i*o
发帖数: 149 | 4
Using command strings output.so, I found the function void foo(void) is
foo_Fv in the shared object.
Thus, we need call
foo = dlsym(handle,"foo_Fv"); instead of
By the way, I am using Redhat 6.2, I don't know why gcc
【在 T********r 的大作中提到】
: try this way:
: gcc -fPIC -shared -o output.so input.c -ldl -lc
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