j***n
发帖数: 9 | 1 I have multiple *.out files in the current directory.
>ls *.out
a.out b.out c.out
I can use the following command to get the file counts:
>ls -l *.out | wc -l
3
And then I want to allocate the file name to an array as the
following;
file[1]=a.out
file[2]=b.out
file[3]=c.out
Does ls has the function to list first, second, third,
...etc file and then I can use a loop to accomplish this?
Like
while [[ file_count -le file_number ]] #in this case, file
number is 3
do
file[file_count]=`ls *.out ?? | a***n
发帖数: 262 | 2 #!/bin/sh -xv
for name in `ls -*.out`
do
do whatever you want
done
【在 j***n 的大作中提到】
: I have multiple *.out files in the current directory.
: >ls *.out
: a.out b.out c.out
: I can use the following command to get the file counts:
: >ls -l *.out | wc -l
: 3
: And then I want to allocate the file name to an array as the
: following;
: file[1]=a.out
: file[2]=b.out
| c*****t
发帖数: 1879 | 3
^^^^^^^^^^^
just
for name in *.out
is enough
【在 a***n 的大作中提到】
: #!/bin/sh -xv
: for name in `ls -*.out`
: do
: do whatever you want
: done
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