wh
发帖数: 141625 | 1 你看我前面贴的那张，说不定能逆过来。还有我觉得下面这段挺对的，就是个optical
illusion，和左右半脑分工特点无关——不过最后那句“is
hardly a no-brainer”是不是用错了，是不是应该去掉hardly，他的意思是说这事儿
就是个no-brainer，不用费脑筋吧？：
发信人: John123 (悠悠渔家), 信区: Zhejiang
标 题: Re: 一张神奇的图片 (转载)
发信站: BBS 未名空间站 (Fri Jan 11 15:04:35 2013, 美东)
查了一下，好几年前的事。左，右脑说法还是不能确定。还是很有趣。
下面的连接有分析和不同人的感受。
http://scienceline.org/2007/10/ask-hsu-spinning-girl-right-left
“Believing in left brain or right brain people also fails to account for
the human brain’s mysterious flexibility and plasticity. People... 阅读全帖 |
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i*****s
发帖数: 15215 | 2 【 以下文字转载自 Animals 讨论区 】
发信人: iForpus (coelestis), 信区: Animals
标 题: 秋天的堪察加 最美的季节
发信站: BBS 未名空间站 (Thu Jul 5 16:54:01 2012, 美东)
Fall has finally come to the Kronotsky Nature Reserve. Animals enjoy the
abundance of food and prepare themselves for long and severe winter.
Usual for the Kronotsky Nature Reserve pictures.
One of Villain’s children patrols the bank of the lake.
The abundance of easily accessible food made the bears’ bellies look like
the beer ones.
One of the bears often comes close to... 阅读全帖 |
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G**t
发帖数: 276 | 3 Unclogging Toilet Drains
A clogged toilet is one of the most common household plumbing problems. If
your toilet overflows or flushes poorly, try clearing it with a plunger. A
plunger uses air to force clogs out of drains, so it's easy to use and doesn
't damage pipes. If you use a hand snake or a closet snake – one made
specifically for use inside toilets – take care that you don't bang the
porcelain sides of the bowl. Porcelain is tough – up to a point. You wouldn
't want to crack your toilet a... 阅读全帖 |
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i****a
发帖数: 36252 | 4 PS'ed
when the motorcycle is going forward from right to left on the picture, the
wheels are turning counter-clockwise. so if the wheels are rubbing the frame
, the top of the wheel is going from right to left.
However the sparks are flying out towards the right, the opposite direction
of the wheel. thus impossible. |
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o*****s
发帖数: 1445 | 5 u can kick her as u did before. u can ask liaoliao to help u
install a wheel in her stomach and set it as clockwise
rotate.
u offer us a good example but i can not help u. so sorry. |
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P***a
发帖数: 4213 | 6 ☆─────────────────────────────────────☆
sunnymimi (抓不住的才是真的) 于 (Tue Oct 2 05:56:41 2007) 提到:
想用海纳的穿梭。。。。。
☆─────────────────────────────────────☆
clockNULL (always clockwise) 于 (Tue Oct 2 12:56:12 2007) 提到:
在升级，已经升了好久了
☆─────────────────────────────────────☆
Panda (太能猫) 于 (Tue Oct 2 13:25:36 2007) 提到:
想穿哪里？
☆─────────────────────────────────────☆
sunnymimi (抓不住的才是真的) 于 (Thu Oct 4 11:28:11 2007) 提到:
88
☆─────────────────────────────────────☆
Panda (太能猫) 于 (Thu Oct 4 |
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P***a
发帖数: 4213 | 7 ☆─────────────────────────────────────☆
coyun (coyun) 于 (Mon Jun 30 22:31:34 2008) 提到:
相比以前的按专业填志愿？
☆─────────────────────────────────────☆
clockNULL (always clockwise) 于 (Tue Jul 1 00:36:49 2008) 提到:
学化学的大一的时候也学数学分析
☆─────────────────────────────────────☆
TechniColor (坚决服从rourou的领导) 于 (Wed Jul 2 14:28:42 2008) 提到:
恩
这是个好的发展方向
不光要学数分，最好也学点正谨的物理，至少量子力学什么的
这两天那海归版大坑，看学校发展，
发现合并前，浙大比那些纯粹的工科学校
最大的优势就是有个理科，虽然不怎么样，不过比没有还是完全不一样的
重建浙大理科的那任校长是很有眼光阿
☆───────────────────────────────────── |
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w****u
发帖数: 69 | 8 这好像是老黄的一贯作风啊，呵呵
发信人: clockNULL (always clockwise), 信区: ZJU
标 题: Re: 浙大论坛透露副教授患癌引2千名学生回应
发信站: BBS 未名空间站 (Tue Feb 2 21:39:25 2010, 美东)
要是开学第一节课就立了规矩，就没什么好说了
我们上拓扑的老黄就这样
要是平时没事，有一天突然这样就有点问题了 |
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J*****3
发帖数: 525 | 10 查了一下，好几年前的事。左，右脑说法还是不能确定。还是很有趣。
下面的连接有分析和不同人的感受。
http://scienceline.org/2007/10/ask-hsu-spinning-girl-right-left
“Believing in left brain or right brain people also fails to account for
the human brain’s mysterious flexibility and plasticity. People who had
half their brain removed encounter some problems – like not being able to
move or see from one side of their body – but largely retained or relearned
mental abilities such as language in their remaining brain hemisphere. All
this research cle... 阅读全帖 |
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J*****3
发帖数: 525 | 11 查了一下，好几年前的事。左，右脑说法还是不能确定。还是很有趣。
下面的连接有分析和不同人的感受。
http://scienceline.org/2007/10/ask-hsu-spinning-girl-right-left
“Believing in left brain or right brain people also fails to account for
the human brain’s mysterious flexibility and plasticity. People who had
half their brain removed encounter some problems – like not being able to
move or see from one side of their body – but largely retained or relearned
mental abilities such as language in their remaining brain hemisphere. All
this research cle... 阅读全帖 |
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p**o
发帖数: 3409 | 12 Here is how I have been using Logitech M570.
http://www.youtube.com/watch?v=IIlLZyxhCrI
I picked the right-handed version for my left hand,
and turned the orientation by 90 degree clockwise
in Logitech setting panel.
It took me a few days to get used to it,
but it works like a charm.
My right-hand mouse is an ordinary one though.
I alternate between them to relieve my hands. |
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H*M
发帖数: 1268 | 13 I think the assumption is too strong(clockwise is even stronger than sorted)
but i guess this is the way..otherwise how could it be possible...
多边 |
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r*****d
发帖数: 54 | 14 our group is doing a kind of MC simulation, I find the 32 bit code
can run 20% faster on Opteron vs the same clockwise 32 bit CPU such
as Athlon MP. I suppose this is because of the CPU operation is 64 bit,
so memory operation is faster such as memcpy() can be accelerated
twice faster. Not so sure...but when I try to compile the code using
64 bit compiler, it is tough... |
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l*******G
发帖数: 1191 | 15 what's node1 node2 and what does i have to do with line()?
When collecting, how to prove the collected segments are in clockwise order
of the polygon points? |
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x*****w
发帖数: 8 | 16 the max number of nodes connect is small, less than 20. Try use dynamic
array like list. one line only check the smaller node, otherwise you
duplicate each line.
clockwise is easy just search online. |
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l*******G
发帖数: 1191 | 17 what's node1 node2 and what does i have to do with line()?
When collecting, how to prove the collected segments are in clockwise order
of the polygon points? |
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x*****w
发帖数: 8 | 18 the max number of nodes connect is small, less than 20. Try use dynamic
array like list. one line only check the smaller node, otherwise you
duplicate each line.
clockwise is easy just search online. |
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l***o
发帖数: 7937 | 19 From the 2n+1 vertices, randomly select a vertex, say A. Then select
vertices B and C clockwise. Denote angle AOB by p*a, angle BOC by q*a, where
a=2*pi/(2n+1); p, q are both integers. For the center to lie inside
triangle ABC, the triangle must be acute. Therefore,
0 < p*a/2 < pi/2
0 < q*a/2 < pi/2
0 <(2*pi-p*a-q*a) < pi/2
which can be further simplified as
1 <= p <= n
1 <= q <= n
n+1 <= p+q <= 2*n
The number of (p,q) pairs that satisfy the conditions above can be easily
calculated as n(n+1)/2.... 阅读全帖 |
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l******6
发帖数: 23 | 21 You have a circle with a number of ants scattered around it at distinct
points. Each ant starts walking at the same speed but in possibly different
directions,either clockwise or anticlockwise. When two ants meet they
immediately change directions, and then continue
with the same speed as before. Will the ants ever, simultaneously, be in the
same positions as when they started out (in their own starting positions)? |
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s***e
发帖数: 267 | 22 For N points A_1,..., A_n, suppose that they are on half circle. If you
start from any point and collect points in clockwise order, then you get a
list of n points. Obviously, one and only one such list is within half
circle (with probability 1).
WLOG, assume such list start from A_1. Then for the points A_2, .., A_n to
be within the half circle starting from A_1, the probability is 0.5*0.5*...=
0.5^(n-1). Consider symmetry, the result is
0.5^(n-1) * n
In the case of 3 points the result is 3/4. |
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c****o
发帖数: 1280 | 23 well, think about the second in terms of random walk, for clockwise +1, for
counterclockwise -1, then the problem transfer to what is the expected time
to first reach +3 or -3, and this is easy. |
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M********t
发帖数: 163 | 24 如果是你这么理解的题，确实是简单。但这是个三维空间，何来clockwise?
for
time |
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n******m
发帖数: 169 | 25 not sure.
1. cov(x,y)/var(y)
2. 6/11
3. (99%)^100, estimate 37.5%, calculator says 36.6%.
if corelated, can be max 99% min 0%
4.....
5. Set E(x)=0. Suppose pdf exist. need to prove int(e^xf(x)dx))<=1. Let F(t)
=int(e^(tx)f(x)dx), then F(0)=1, F'(t)<0, So F(1)<=1.
6. Fix one vertex, consider clockwisely the first ray going out from this
vertex, it divids the polygon into 2 part. Then triangulate the 2 parts. To
gaurantee on overcount, the first part should not have any ray coming out
from the... 阅读全帖 |
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k*****y
发帖数: 744 | 26 我觉得也是1/4。
考虑圆心不在三角形中的probability，就是说三个点到圆心的夹角在一个pi里。这时
有且只有一个点，使得其它两个点在它clockwise方向pi以内。所以这个概率是
3*1/2*1/2。于是在三角形中的概率就是1/4。 |
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l******i
发帖数: 1404 | 27 You have a circle with a number of ants
scattered around it at distinct points.
Each ant starts walking at the same speed
but in possibly diff erent directions, either clockwise or anticlockwise.
When two ants meet they immediately change directions,
and then continue with the same speed as before.
Let us ignore the collisions,
just think of the ants walking through each other.
Clearly there will then be a time at which
the ants are simultaneously in their starting positions.
But how to prove th... 阅读全帖 |
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k*****y
发帖数: 744 | 28 假设速度是1，圆的长度也是1。
case 1: 如果都是同一方向
t=1时，会回到原来的状态。
case 2: 设有p个clockwise，q个counterclockwise，pq != 0。
画个图应该可以证明在t = p+q时，会经过2pq次碰撞，回到了原来的状态。 |
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x*********i
发帖数: 55 | 29 This is my two cents: label the ants clockwise from 1 to n, after a time of
T = cycle length/speed, you get a permutation of the ants. Because every
permutation has a finite order (denoted by p), after a time of T*p, every ant is in its
original position as well as direction. |
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d******e
发帖数: 17 | 30 The first question is simple. Fix one point. Then clockwise there are three
arcs with total length 1. Denote the the length of the three arcs as a,b,c.
Then we have a+b+c=1, a>0, b>0, c>0. Use c=1-a-b, then 0
Now we know the density for a and b is uniform in the triangle area (0
0
the triangle ABC, Denote points A=(0,0), B=(1,0), C=(0,1),D=(1/2,0), E=(0,1/
2), F=(1/2,1/2). See the following figure.
C|\
| \... 阅读全帖 |
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s***e
发帖数: 267 | 31 You can number all points 1..N, and then the probability of all points fall
in the half circle starting from 1 (clockwise) is 1/2^(N-1).
So I think the overall probability is N/2^(N-1) by symmetry. |
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m**i
发帖数: 89 | 32 Defining a Hurricane
The definition of a hurricane is simple and contains the following components:
Hurricanes are tropical - they are generated in tropical areas of
the ocean near the equator
Hurricanes are cyclonic, meaning that their winds swirl around a
central eye. Wind direction is counterclockwise in the northern
hemisphere and clockwise in the southern hemisphere.
Hurricanes are low pressure systems. Atmospheric pressure in
the eye is always a low pressure area. The lowest ba |
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m****i
发帖数: 159 | 33 just a rough guess:
n/(2p,n) should be the minimum period. if the initial condition has a
symmetry of k, then the minimum period should be divided by k.
n balls ( neglect its radius ), p clockwise.
rules. |
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S*********g
发帖数: 5298 | 34 First, let us assume the length of the circle is 1
and the velocity is 1 and we start at time 0.
We will call the balls with counter-clockwise speed as p-ball
And the ball with cloclwise speed will be called as m-ball.
Second, let assume that there is no rotational symmetry in the initial
configuration. As pointed out by Mengyi, the period will be devided by
a factor of k, if the system has k-fold rotational symmetry.
Observation 1: Suppose ball i is a p-ball, from time 0 to 1,
i will have colli |
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c*******n
发帖数: 718 | 35 xx-wise means in the manner of "xx".
xx ususally is a noun. For example, clockwise, piecewise, nationwise. |
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h********t
发帖数: 189 | 36 题有点长， 万分感谢
Assume that we have a group of n+1 people sitting around a round table.
Assume that there is a token circulated along the round table, and a person
can speak only if he/she obtain the token. We assume that the time that a
person can hold the token, once receiving it, is exponentially distributed
with the mean value of x seconds. At the end of this time, the token then
has to be passed in the clockwise or counterclockwise direction with the
same probablility (i.e. 50%) to the neighbori... 阅读全帖 |
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B****e
发帖数: 1900 | 37 这样啊？咦，不是把clockwise也放进来了么？难道那个也是秘密的？ |
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l******u
发帖数: 2314 | 38 支持！佩胡！小雪牛X！
看看我下面的部分不同于小雪的版本：
G大调的悲伤 Sadness in G-Major
如果爱下去 If Love Goes On
个人秘密 Personal Secret
我用所有报答爱 All for Love
天下无双 The Only One
瞬间倾心 恒久钟情 Forever and Ever At First Sight (还是忍不住说一声这首歌实
在是很难听)
小雪的Typo:
逆时针 Counter-Clockwise
放轻松 Just Relax |
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F*********e
发帖数: 2696 | 39 http://hubpages.com/hub/v-twin-engine
“However, many motorcycle manufacturers have corrected for torque reaction
by rotating the transmission input shafts and the balance and drive shafts
opposite that of the crankshaft so that there is approximately equal mass
turning clockwise and counterclockwise at any time, thereby physically
canceling the effect.” |
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m****y
发帖数: 3437 | 41 Good point! Thanks
Then it is making a square counter clockwise and then repeat. |
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A**u
发帖数: 2087 | 42 从三到四是counter clockwise ah..
instead |
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p*******r
发帖数: 100 | 43 Regarding #40, does this "bet" apply to raise too? If A bets, B raises, A
calls. Who shows first? B?
Is there any case that one must show if he already loses to someone showed
earlier?
40. At showdown, the player whose bet was called must show first. In the
event there was not bet, the player left of the button shows first and so on
clockwise around the table. |
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i***l
发帖数: 4182 | 44 ☆─────────────────────────────────────☆
airtraffic (不再为悲喜伤怀) 于 (Thu Jun 5 18:07:28 2008) 提到:
How smart is Your Right Foot?
Just try this. It is from an orthopedic surgeon............This will boggle
your mind and you will keep trying over and over again to see if you can
outsmart your foot, but you can't. It's preprogrammed in your brain!
1. While sitting where you are at your desk in front of your computer, lift
your right foot off the floor and make clockwise circles.
2. Now, while |
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