Maths Problem for help! Thanks a lot! - SanFrancisco版 - 未名存档

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SanFrancisco版 - Maths Problem for help! Thanks a lot!

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a*****g 发帖数: 1320	1 SOLVE FOR X. 2X^2 -5bx+4cx-10bc=0
g*********e 发帖数: 14401	2 if ax^2+bx+c=0 then x=(-2b +/- sqrt(b^2-4ac))/(2a)
a*****g 发帖数: 1320	3 Yes. Thanks a lot. 【在 g*********e 的大作中提到】 : if : ax^2+bx+c=0 : then : x=(-2b +/- sqrt(b^2-4ac))/(2a)
h*****1 发帖数: 151	4 (2x-5b)*(x+2c)=0; x=-5b/2 or x=-2c;

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