o*******n
发帖数: 6500 | 1 桌上
AJ9x
Txx
J87
QJ7
手上
Q
A98
QTx
AT9643
叫牌简单
2C-3C //
本来做不成的
但首功小草花
2 Q x x
打草花7 RHO 示缺，放给K
转攻方块6，RHO K，兑现方块A，再打第三轮方块，很好的方块J停在明手
现在的桌上
AJ9x
Txx
-
J
手上
Q
A98
A9xx
这个牌还能打宕吗？ |
|
o*******n
发帖数: 6500 | 2 还有一副3N 敌方没有参与叫牌
1C-2C
2S-3C
3H-3N
桌上
AT9xx
AKJ8x
A96
-
手上
-
Q5
J8753
AJ8542
首攻 H T, 桌上A吃，飞方块9输给LHO的T
回攻黑心3，9 被RHO的K捉，回攻黑心2， A吃住Q
解封红心Q，兑现方块A，方块最后投给了RHO
黑心5出来
大家判断J在哪边吧
呵呵 |
|
p***r
发帖数: 20570 | 3 The thinking process can be different at the table. According to what you
have said, RHO showed DAK, stiff C and a possible H honor. So Shi Miao might
think that it is rather safe to take the S finesse, which may allow him to
make an overtrick, because with hands like:
SKxxx HQxxx DAKxx Cx, RHO would usually double 3C as a take out.
Shi Miao's bridge is way stronger than most (or perhaps all) on this board.
I still remember when I was a college bridge player more than 15 years ago in Beijing, I ... 阅读全帖 |
|
o*******n
发帖数: 6500 | 4 对方有局
RHO 第一家开叫
RHO SHO LHO CHO
1C - 1S x
xx - - 1N
- - x xx
- 2C - -
x xx - 2H
x - 2S -
2N //
持有
JT4
764
AJ6
9654
攻啥？ |
|
o*******n
发帖数: 6500 | 5 对方有局
RHO 第一家开叫
RHO SHO LHO CHO
1C - 1S x
xx - - 1N
- - x xx
- 2C - -
x xx - 2H
x - 2S -
2N //
持有
JT4
764
AJ6
9654
攻啥？ |
|
a****s
发帖数: 524 | 6 came across an interesting hand:
Both,
N
S JT4
H J432
D KQT7
C J8
S
S AQ92
H Q
D 962
C AT976
RHO (a robot) opened 1NT (15-17) at 1st seat, I came in with 2S, showing
Spade and a minor, and allowed to play there.
LHO (not a robot) led Ten of hearts,
robot won the King and continue the ace,
I ruff try a low diamond, LHO put on the ace and play another
diamond, looks like Ax. I win Q in dummy.
J of club got covered by Q and Ace, I play another club to robot's K.
diamond back and RHO ruffed with S3.... 阅读全帖 |
|
a****s
发帖数: 524 | 7 The consensus (among national champions or better) was:
1. RHO pass, divided between 3D (constructive raise) and 3S, or even 2S.
2. RHO 2C, most would bid 3S, with outliners of 2S and 4S.
I think case (1) is a matter of taste and habit, I personally don't
subscribe to the idea of preempt with nothing. And 3S bars their 3H.
However I agree 3D does have a merit of refined hand evaluation.
case (2). I really couldn't see the benefit of bidding 2S.
3S or 4S is a matter of judgement. This is not sayi... 阅读全帖 |
|
i****e
发帖数: 642 | 8 Thanks. You are right. It is not easy for me to count to 13 :)
The S block may help only if we find RHO discards on first or second D. Then
we play C, and hope RHO has CAK and blocked S. |
|
b***y
发帖数: 2804 | 9 如果准备将吃梅花，这个牌在先期要作个猜断，LHO是两张还是三张将牌。第一种打法
，你猜LHO是两张，那么就掉一轮将然后打梅花到CK，接着继续梅花，准备由明手将吃
第四张。第二种打法，打LHO三张将，那就拔两轮将牌，然后梅花到CK再出梅花给右手。
即时你猜错，这两种打法仍有机会。第一种情况，假定左手实际是三张将牌，你出小梅
花，左手将吃，方块到同伴DA，再将吃梅花，红心脱手；你HA拿住，仍有飞DQ的机会。
第二种情况，假定左手实际是两张将牌，你打第三轮梅花后，RHO拿住并吊第三轮将牌
，你明手SQ赢，还有打RHO方块AQ的机会。
总体感觉是第一种打法综合机会更大些。 |
|
i****e
发帖数: 642 | 10 Yes, it is better to play x to Q.
Play A then to Q: succeed if RHO holds Jx (3 combinations) while the other
way fails;
Play x to Q: succeed if RHO holds XX (3 combinations) or singleton 9 while
the other way fails.
The second way also has the advantage to get 3 tricks while losing only 1,
as the real layout. |
|
w****b
发帖数: 623 | 11 Here's another hand.
Both vul, you hold
-
KJT872
J75
QT73
your LHO opened a precision 1S, pd overcalls 2C. RHO jumps to 4S. What now?
If you bid 5C (or 4N which pd corrects to 5C), RHO follows with another 5S.
Do you give up here or continue also?
One |
|
i****e
发帖数: 642 | 12 That is a likely layout, although it may not be necessary to play C to J
first.
How about this line? First try C to K. If it loses to A, next try C to J. If
it also loses, go back to D finesse. This line works if RHO has CA, or LHO
has CQ, or LHO has DQ. The chance to fail is about 1/8 = 12.5%.
My previous line to end-play LHO fails if RHO has
exactly D Qxx, and
mis-guess C or there is no guess (LHO CAQ).
The chance to fail is about 0.36 / 2 * (0.5*misGuess + 0.25) = 4.5 to 13.5%
where 0.5 is th... 阅读全帖 |
|
b***y
发帖数: 2804 | 13 Very unlikely that RHO is ducking DQ. But even with 5 diamond tricks, I only
have 11 top tricks. As I said, this is not a great slam, although hardly
the worst I've seen.
I think S9 makes spade suit more attractive for developing the additional
trick. Options are:
1) Finesse SJ, if lost then later finesse S9. 75% chance.
2) Finesse SJ, if lost then later play AK for drop. In addition to LHO
holding SQ, it also works if S are 3-3, or ten-doubleton. Somewhere around
77%.
3) Cash AK, then 3rd spade... 阅读全帖 |
|
b***y
发帖数: 2804 | 14 S8 and S9 are useless. Maybe they prevent LHO from unblocking from KT or QT.
Another legitimate line is to clear clubs then play low spade from hand,
hoping LHO has both SKQ. But first, he may be leading SK with that holding;
second, that will leave RHO with almost nothing (but RHO cuebid 4D). |
|
b***y
发帖数: 2804 | 15 4D bid was strange anyway. Unless with shape such as 2-6-0-5, RHO just has
too many losers to make slam try when partner could only make a simple 1-
level overcall.
It's also not very likely for RHO to have both SKQ -- that would mean LHO
has no honor outside of hearts, which that hand LHO might have overcalled 2H.
Sometimes it is useful to know how reliable the opposing bids are. |
|
p*********6
发帖数: 679 | 16 I see - it's attitude lead. In this case, h2 should be count, right? since
the count information helps partner more (declarer won't be able to tell if
LHO is 5/4/3-cards). If h2 is count(std), that means LHO is hAQxx3. I can't
see how declarer is going to make it. Whenever LHO/RHO gets in, LHO can cash
hA to drop the declarer's bare K (based on count) - 5 tricks already.
If h2 is not count, then h is probably 4-4 (LHO not likely to lead from AQ3)
.I'll try to avoid RHO getting in. Run s8 (to pla... 阅读全帖 |
|
i****e
发帖数: 642 | 17 IMP both red.
Pard RHO You LHO
P 1D P 1H
P 1N P 3N
RHO's 1D and 1N show 11-13 points. You don't think your hand is good to
preempt at red.
If you had only 5S, that will be a natural lead. Now you have 6. Without
other entry, the chance to cash spade suit becomes worse. Do you still lead
S or try something else?
KJT643
8543
64
6 |
|
i****e
发帖数: 642 | 18 Yes, not covering HQ is wrong most of time. So I think it is reasonable to
think RHO has no HK if not covered. (50% HK onside)
Then after LHO is in with HK, it is also reasonable to assume he will not
play C if he has CK. Otherwise he should play C no matter what he has in C.
So if he gives sluff and ruff, we will try to drop his CK. (chance 1/12).
This ends up the total chance of 54%.
At this situation (HK off), the CQ method can still make if LHO has CKxx.
If LHO returns C after in with KH, th... 阅读全帖 |
|
i****e
发帖数: 642 | 19 That sounds a good analysis. So we are comparing 3 lines, not 2.
(1) Q to A fails if LHO is void.
(2) J then Q fails if RHO has stiff K.
(3) J then 9 fails if RHO has K8 or Kx.
Both of above is a single case, and stiff K is a little higher probability,
but is almost negligible. But with possible line (3), starting with J still
seems much better.
theory
taking
rate.
how |
|
i****e
发帖数: 642 | 20 Here is an interesting hand. First let's make it an opening lead question.
You hold
7
KT862
K9852
K5
your pd passes, and rho opens 1S. Since it is red vs white, you decide to
keep quiet.
Pd RHO You LHO
P 1S P 1NT
P 3S P 4S
What will you lead? |
|
i****e
发帖数: 642 | 21 I had thought Q or 8 is a pure guess. It is nice to point out that the D8
is better to take care of KJxx in RHO.
What is in my mind is to play a heart, LHO plays HT, dummy ducks and RHO
discards a spade. Now we have 10 tricks. The only return for LHO is a heart.
Do you think this improves or hurts the chance?
clue |
|
b***y
发帖数: 2804 | 22 Why is RHO thrown immediately? Say RHO returns a heart, do you finesse with
9 or play Q? |
|
b***y
发帖数: 2804 | 23 Why is RHO thrown immediately? Say RHO returns a heart, do you finesse with
9 or play Q? |
|
i****e
发帖数: 642 | 24 Try DKQA first. If LHO has 4D, cash SKQ. If LHO also has long S, it is a
simple squeeze.
If RHO has 4 or 5 D, after we have only 3S in dummy and hand, RHO may have
shown 4-3 or 5-2 in minors, then major holding can be 4-2 or 1-5, and guess
is still needed. No guess needed for all other holding.
Still not 100% ... |
|
i****e
发帖数: 642 | 25 Team match, decent opps.
white vs red:
Pd RHO You LHO
P P P
1C 1NT X P
2D 2S 3NT AP
1C: precision
1NT: one suit
4
J85
AKT95
AKJ2
QT8
AK72
872
753
You are in 3NT. Lead S2, SK win, and return S3. Your Q wins.
What is the best chance?
============================================
Another 3NT. Again white vs red if it matters:
RHO You LHO Pd
2S 2NT P 3NT
AP
2NT: stronger than 16 points
875
KQ9
J98732
Q
AQ2
A4
QT4
AK987
Lead SJ, covered by K. Where could be the 9th trick? |
|
r**********n
发帖数: 3914 | 26 If you want to trade options successfully, you really need to put at least 2
years into learning how to trade them. there are so many factors influcing
its pricing: delta, gamma, vega, theta and rho. Rho is the least element
that you need to worry about, because it is a "constant". It represents the
interest rate at a particular period. Delta represents the movement of the
stock price. Gamma represents the movement of the dalta. Vega is the value
of volatility. and theta is the value of time. D... 阅读全帖 |
|
l****t
发帖数: 1580 | 27 ☆─────────────────────────────────────☆
tuantuan007 (团团三少爷的剑) 于 (Mon Mar 12 11:59:18 2012, 美东) 提到:
祝她生日快乐。
☆─────────────────────────────────────☆
fanfaner (烦烦) 于 (Mon Mar 12 12:01:48 2012, 美东) 提到:
吃
☆─────────────────────────────────────☆
donthurtme (烦着呢) 于 (Mon Mar 12 12:04:34 2012, 美东) 提到:
chi
☆─────────────────────────────────────☆
Jingqg1979 (79) 于 (Mon Mar 12 12:05:35 2012, 美东) 提到:
贺寿!
☆─────────────────────────────────────☆
meflying (吾飞) 于 (Mon Mar 12 12:06:23 201... 阅读全帖 |
|
l****t
发帖数: 1580 | 28 ☆─────────────────────────────────────☆
tuantuan007 (团团三少爷的剑) 于 (Mon Mar 19 11:06:10 2012, 美东) 提到:
终于走了，这个周未过的开心，来发包子大家同乐。
☆─────────────────────────────────────☆
fanfaner (烦烦) 于 (Mon Mar 19 11:07:12 2012, 美东) 提到:
你一周失几次恋？
☆─────────────────────────────────────☆
zkjeffrey (嘟嘟) 于 (Mon Mar 19 11:08:20 2012, 美东) 提到:
bless~
☆─────────────────────────────────────☆
donthurtme (烦着呢) 于 (Mon Mar 19 11:10:21 2012, 美东) 提到:
捧场
☆─────────────────────────────────────☆
juto (巨头：英年早肥) 于 ... 阅读全帖 |
|
a***u
发帖数: 4334 | 29 拉力牛顿每米 f
角度theta，用你的数据，是10米/500米=1/50
铁密度rho，半径R，
f\theta=\rho (\pi R^2)g
然后你算一下f多少。 |
|
a***u
发帖数: 4334 | 30 \rho*\pi* R^2*(3L)*g/2/(L/h)=2*最大承受力
\rho 铁密度
R=0.025m
h=10米
g重力加速度
最大承受力，根据你的125kN，
求最长L
L=105米。
这就是原始问题：铁锁最长可以拉多长而不断？
注意这里L >> h，否则公式不成立。
然后江面上隔100米找一个固定点即可。 |
|
a***u
发帖数: 4334 | 31 不是。你这样比很冤枉，他们又不是一场命题作文课上写两篇，然后让语文老师点评，
完全是不同场合写的，比起来就是关公战秦琼。
很明显rho迅在凑字数，估计是按照字数拿钱发帖，所以读日本书后面叽叽歪歪写上一
大坨，和杂志社骗稿费，当然这一大坨比较适合装逼的小学生阅读。
作人那篇一看就是心情不好写的，查了一下，果然，这篇插在一本散文集里，前面都是
什么论骂人，论剽窃什么的，骂完街以后气鼓鼓来上一篇，而且散文集也不能扯谈太多
靠字数拿钱，是靠发行册数拿钱的，所以篇幅短比较轻松。
另外我保证rho讯出门溜达肯定带着周作人，一个12岁一个8岁，刚好是大哥带小弟溜达
的年纪。他妈让老大看好老二，要是出门弄丢老二，打断你的狗腿。后来迅哥和作人翻
脸了，所以死也不提弟弟，阿猫阿狗邻居亲戚提了一大堆，就是不提弟弟。 |
|
a***u
发帖数: 4334 | 32 作人老婆被rho讯偷窥了，为了男人的尊严只能和rho讯绝交了，但是还没有到反目成仇
的地步吧，最多是不来往了，不联络了，有时候作人想想兄弟如手足，妻子如衣服，回
想起小时候和迅哥一起玩的日子，还是能怀念讯哥的。他们不争遗产，两人都是倭杂，
本质还是很像的，只是为了一个女人搞成这样，作人也太不刘备了。再看看三弟，家里
养着大和抚子，外面保养着小三，活得多快活，何必为了一个女人和兄弟翻脸。
其实作人当初也是不行，有点自私，兄弟住一起的时候，作人每天晚上和老婆发出各种
销魂的声音，那边迅哥一个人只能自己撸，饥渴难耐，去偷窥一下洗澡也算是男人可以
原谅的错误。作人本来就应该带着迅哥去八大胡同好好乐，保证兄弟关系和好如初，弟
媳白给都不要。马寅初马老贼在北京夜夜嫖娼，陈独秀也是个中高手，现在两人形象都
不错，周家弟兄就是想不开，迅哥在找到许广平之前，做了大半辈子处男，根据他自己
说，只和老家的文盲老婆做了两三回，在北京天天撸一个姓马的北大校花，人家也不嫁
给迅哥。 |
|
k**********g
发帖数: 989 | 33 本人物理僅到高中一半的程度
有錯請拍磚
純粹靠猜
A = area of hole
圖三，正在自由落下的水柱段的重量不會在天平顯示出來(rho * g * h * A, h is
much smaller than water depth)。
圖二，底部孔洞打開的一瞬間(time = zero plus)，天平讀數會立刻減少(rho * g * h
* A, h same as water depth)，如同缺少了一個圓柱體的水柱的質量。
圖一，沒看懂。據說工科大一開始時就是學這些，我沒學過。也不曉得為甚麼水壓可以
改變施壓的方向。 |
|
H********g
发帖数: 43926 | 34 如果是琼瑶剧，研究一下男主角失恋之后去雨中净化心灵的情节，这种情况下一般来说
是总路程不确定，但是总时间确定，所以当然是单位时间里沾水越多越爽。因为顶面沾
水是（rho）Avt，是个跟时间成正比的简单关系，人的活动没法影响，而前面沾水是（
rho）Bwt，w是人的速度，所以单位时间里跑得越快，前面沾水越多。这就是净化心灵
的时候狂奔会感到更爽的科学原理。
伟大领袖毛主席自述年轻时为了文明其精神野蛮其体魄，经常于下雨时知乡下无人处除
衣裸奔，口呼“哦罗罗”。这说明主席虽然数学不及格，但是并不妨碍他从实践中发现
真理，并再付诸于实践。 |
|
o**1
发帖数: 6383 | 35 据历史学者杰瑞·本德利称，即使未能确切证实两个宗教的关系，但可以肯定的是两教
关于耶稣和佛陀出生、生平、教诲及死亡的形容都有相似之处。[37].
[编辑] 行政架构
佛教寺院制度和基督教修道院有以下几点相似：
* 两者都遵从清贫简约和独身的修行生活[38]
* 基督教大公会议和佛教集结相似，都是聚集僧侣去辩论教义，以制定正宗的经文
* 佛教在各地传教并建立寺院，而一些基督教寺院是在差不多同时同地建立起来，
如在阿历山大城和土耳其的安条克(Antioch)
[编辑] 佛陀与耶稣
释迦牟尼和耶稣有以下几点相似：
1. 诞生的传说：释迦牟尼的母亲摩耶夫人梦见白象从左侧进入身体，童贞怀孕，并
有僧侣预言儿子将会是君王或伟大的佛陀，后来从右侧产下释迦牟尼。圣母玛利亚梦见
天使，预言儿子会是地上的君王，童贞怀孕，后产下耶稣。[39]圣母抱着耶稣的雕像有
如佛母抱着释迦牟尼的雕像。
2. 棕榈向玛利亚弯曲，正如无忧树向耶输陀罗弯曲一样。
3. 关于耶稣初生时先知西面以及强光的描述几乎和佛陀初生时一样
4. 关于麻雀复生的神迹
5. 犹大背叛耶稣，... 阅读全帖 |
|
S*****T
发帖数: 400 | 36 【 以下文字转载自 Physics 讨论区 】
【 原文由 susygut 所发表 】
发信人: Newton (牛顿), 板面: Science
标 题: 爱因斯坦自述（10）
发信站: 飘渺水云间 (Mon Feb 14 12:53:48 2005), 转信
因此，由于引进场而开始的革命，决没有结束。那时又发生了这样的事：在世纪交替时
期，同我们刚才讨论的事情无关，出现了第二个基本危机，由于麦克斯。普朗克对热辐射
的研究（1900）而突然使人意识到它的严重性。这一事件的历史尤其值得注意，因为，至
少在开始阶段，它并没有受到任何实验上的惊人发现的任何影响。
基尔霍夫以热力学为根据，曾得到这样的结论：在一个由温度为 T 的不透光的器壁围住的
空腔里，辐射的能量密度和光谱组成，同器壁的性质无关。这就是说，单色辐射的密度
\rho 是频率 \nu 和绝对温度 T 的普适函数。于是就产生了怎样来决定这个函数
\rho(\nu,T) 的有趣问题。关于这个函数，用理论方法可以探知些什么呢？按照麦克斯韦
理论，辐射必定对腔壁产生一个压力，这个压力是由总能量密度决定。
由此，波耳兹曼由纯粹热力学方 |
|
c**r
发帖数: 51 | 37 用\mathrm{Min}_\rho会把\rho标记到右下角，\DeclareMathOperator{\Min}{\mathrm{
Min}}不work... |
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c**r
发帖数: 51 | 38 ft，被告知注册不满三天不能回复。
为什么需要quantum atom很好的移植性呢？比如同样是氧原子，在O2,H2O2,H2O中的环
境明显是不同的，zero-flux移动也是很正常的。
“另外AIM所得到的原子偶极矩在某些条件下可能连方向都不对”
AIM对电子密度分割，偶极矩通过sum_i ZiRi - \int \rho(r) dr计算。划分了 \rho(r
)，相当于将积分限分为了几个部分，再加合应该可以得到整个空间的积分范围.
另外所谓正确的原子偶极矩的方向是相对什么而言的？电中性的偶极矩为零，不是电中
性的和坐标选择有关，可以是任意数值。这个量的计算有多大意义呢？
其定量界 |
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L*******g
发帖数: 913 | 39 边界值问题的2阶PDE，Numerical Recipe给的程序是mglin()，具体操作本人一时难以掌
握，希望有经验的人指点一二。具体如下：
方程u''(x)+u''(y)=rho, 边界条件f(x,y)=0
1. mglin()里说一开始输入的u(n,n)里应该包含rho，具体应该怎么包含？
2. 边界条件f(x,y)=0在程序的什么地方输入？
3. resid()中的res[i][1]=res[i][n]=...=0是否要根据我的边界条件修改？ |
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w*********r
发帖数: 488 | 40 原题如下：
given function V in terms of S and t,V(S,t)
parameters are:rho,alpha,lambda,theta,mu,sigma
the PDE is:
rho*V(S,t)=alpha*S+lambda*(mu-S)*Vs(S,t)+theta*(Vs(S,t)).^2+0.5*sigma*(S-S.^2)*Vss(S,t)-Vt(S,t)
S is in [0,1],and t is in [0,T],T is a constant.
the boundary condition is V(S,0)=0
Vs is the first-order partial derivative of V wrt S, and Vt is first-order partial derivative of V wrt t.
昨天晚上在MATLAB里面我试了approximation+Broyden method，因为发现Broyden有现成的function（也我们老师自己编的，不是MATLAB自带的），newton那个总说有错误 |
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y***d
发帖数: 2330 | 41 \int dx rho(x) = \sum_i rho(x_i) = A 是不是好像可以算成线性约束？会不会就间
的了？
我只是做物理的 model 偶尔用到一下 |
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d*******d
发帖数: 3382 | 42 哪里来的问题？
如果rho是一个标量数字，难道不是A=B*rho? |
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s********k
发帖数: 6180 | 43 实际的问题，除了B和rho还可以加其他的参数，比如error扰动之类的。但是希望函数
中一定要包含B和
rho |
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n*****a
发帖数: 64 | 44 if the total pressure (P0) is specified (such as a flow discharged from a
big tank), and if the flow rate (V) in the tunnel is also known (while
usually these two conditions are not given at same time, but the maximum
flow rate should be known anyway), then the tunnel outlet height where
tunnel becomes partially filled can be determined simply by bernolli
equation: P0=rho*V^2/2+rho*g*H+Patm,
Similarly, plugging Vmax in the equation, the lowest possible elevation can
be determined.
See "Siphon Wi |
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t*****e
发帖数: 224 | 46 We have two functions, f and g,
f(x) = sum_i b_i * (x-x0)^i,
g(x) = sum_i a_i * b_i * (x-x0)^i,
where b_i and a_i are constants, and abs(a_i) < 1.
Obviously these two functions are related by a bounded linear operator rho(),
ie, g(x) = rho(f)(x)
Does the operator have a name? Does it have a natural adjoint operator?
Thanks a lot! |
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a*****r
发帖数: 63 | 47 怎么证明??
dw1*dw2=rho(1,2)dt
w1, w2是布朗运动
d为微分算子
rho为相关系数 |
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a*****r
发帖数: 63 | 48 那是怎么得来的??
其实我主要想知道当w1=w2的时候, rho等于多少. rho=1??? |
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w**********y
发帖数: 1691 | 49 怎么证明??
dw1*dw2=rho(1,2)dt
w1, w2是布朗运动
d为微分算子
rho为相关系数
w1是一个布朗运动,w2是另外一个布朗运动。
一个常用例子，比如某stock的价格的波动的volatility是 dw1, 市场上intrest rate
的价格波动是dw2，那么这两种波动可能是independent的，这是一种理想的假设。但是
我们知道现实是相违背的。
所以有模型做dw1和dw2是相关的。一般来说现在做到的地步还只是相关系数是个常数（
不随时间t变化）。现在很多人做公司或者信用卡的default都基于这个。
另外一个neutral science中的模型，刚想到，可能非常有利于理解，具体你可以参看
'hitting lines with two dimensional brownian motion'-Satish Iyengar
两个neuron的single有noise，首先它们有各自本身产生的noise，这个noise我们可以
认为是独立的。但是它们处于同样的环境中，所以它们又有从同样的环境中得到的共同
的noise，这部分是相关的（因为是同样的来源阿） |
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k*******l
发帖数: 69 | 50 ft
the quadratic covariation of two BMs is not necessarily rho*t
this is just model assumption, since time-dependent or stochastic
instantaneous correlation (the rho above) is too hard to estimate/calibrate
rate |
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