J****y
发帖数: 19 | 1 那位大虾能告诉我我的换算对吗？
number molecular weight of this polymer is 495000 g/mole.
The number of atoms in a mer is 15 and the weight of mer =100 g/mile.
The density of the polymer is about 1 g/cm3.
So I am wondering if I can do the following calculation for 1 cm3 polymer
to know how many atoms I have:
Mass=1g=1/495000 mole
#of molecule =1/495000 *avogadro's numer =B
( 这儿， 不知道可不可以这样对POLYMER计算？？？HELP)
# of atoms=B*(495000/100=# of mer/molecule)*15 (# of atoms per mer)
这个计 |
c*s
发帖数: 2145 | 2 I think it is correct.
Provided that during polimerization, there is no WEIGHT LOSS.
【在 J****y 的大作中提到】
: 那位大虾能告诉我我的换算对吗？
: number molecular weight of this polymer is 495000 g/mole.
: The number of atoms in a mer is 15 and the weight of mer =100 g/mile.
: The density of the polymer is about 1 g/cm3.
: So I am wondering if I can do the following calculation for 1 cm3 polymer
: to know how many atoms I have:
: Mass=1g=1/495000 mole
: #of molecule =1/495000 *avogadro's numer =B
: ( 这儿， 不知道可不可以这样对POLYMER计算？？？HELP)
: # of atoms=B*(495000/100=# of mer/molecule)*15 (# of atoms per mer)
|
a****r
发帖数: 4965 | 3 如果是估算还可以，但并不精确。
高分子的分子量本身就是平均值，不准的。
【在 J****y 的大作中提到】
: 那位大虾能告诉我我的换算对吗？
: number molecular weight of this polymer is 495000 g/mole.
: The number of atoms in a mer is 15 and the weight of mer =100 g/mile.
: The density of the polymer is about 1 g/cm3.
: So I am wondering if I can do the following calculation for 1 cm3 polymer
: to know how many atoms I have:
: Mass=1g=1/495000 mole
: #of molecule =1/495000 *avogadro's numer =B
: ( 这儿， 不知道可不可以这样对POLYMER计算？？？HELP)
: # of atoms=B*(495000/100=# of mer/molecule)*15 (# of atoms per mer)
|
a****r
发帖数: 4965 | 4 刚有网友提醒，才发现
要计算1g高分子里有多少原子，这样计算就行，不用分子量：
1g/100(=mole of mers)*15*avogadro's numer
：to know how many atoms I have:
( 这儿， 不知道可不可以这样对POLYMER计算？？？HELP)
【在 J****y 的大作中提到】
: 那位大虾能告诉我我的换算对吗？
: number molecular weight of this polymer is 495000 g/mole.
: The number of atoms in a mer is 15 and the weight of mer =100 g/mile.
: The density of the polymer is about 1 g/cm3.
: So I am wondering if I can do the following calculation for 1 cm3 polymer
: to know how many atoms I have:
: Mass=1g=1/495000 mole
: #of molecule =1/495000 *avogadro's numer =B
: ( 这儿， 不知道可不可以这样对POLYMER计算？？？HELP)
: # of atoms=B*(495000/100=# of mer/molecule)*15 (# of atoms per mer)
|
J****y
发帖数: 19 | 5 Thanks a lot.
【在 a****r 的大作中提到】
: 刚有网友提醒，才发现
: 要计算1g高分子里有多少原子，这样计算就行，不用分子量：
: 1g/100(=mole of mers)*15*avogadro's numer
:
: ：to know how many atoms I have:
: ( 这儿， 不知道可不可以这样对POLYMER计算？？？HELP)
|
