b******g
发帖数: 669 | 1 the statement is true:
the hash code method for a given class can be used to test for object
inequality,but not object equality, for that class.
hascode 和 inequality是什么关系？ |
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p*******r
发帖数: 4048 | 2
是， 美国贫富差距很大的。 花街吸血太厉害了。
http://www.huffingtonpost.com/2009/08/14/income-inequality-is-at-
a_n_259516.html
Income inequality in the United States is at an all-time high,
surpassing even levels seen during the Great Depression, according to a
recently updated paper by University of California, Berkeley Professor
Emmanuel Saez. The paper, which covers data through 2007, points to a
staggering, unprecedented disparity in American incomes. On his blog,
Nobel prize-winning economist and New York Time |
|
h******y
发帖数: 1374 | 3 新浪科技讯 北京时间9月21日晚间消息，汤森路透9月21日公布了年度汤森路透引文桂
冠得主名单，以预测将于10月公布的诺贝尔奖科学和经济学类得主，名单上的科研人员
将有可能成为各项诺贝尔奖的有力争夺者。
每年，汤森路透都会利用其研究解决方案Web of Knowledge™中的数据，根
据诺贝尔奖的生理或医学、物理、化学与经济分类，使用定量数据来分析和预测最有影
响力的研究人员。根据其发表的研究成果的总被引频次，这些高影响力研究人员被授予
汤森路透引文桂冠得主(Citation Laureates)称号，预示着他们可能成为今年或不久将
来的诺贝尔奖得主。
汤森路透是唯一采用定量数据预测年度诺贝尔奖得主的机构，自2002年起，共有21
位引文桂冠奖得主赢得诺贝尔奖。
汤森路透研究服务引文分析师David Pendlebury说：“在科学社群里，若经过分析
和计算，引文可以作为另一种形式的同行评审。一位科学家发表研究成果的被引用次数
越多，这位学者在其同行之中、从学术角度的受敬重程度越高，而这可以作为如诺贝尔
奖这类奖项的预测指标。汤森路透引文桂冠奖是通过成熟完善的方法评估引用... 阅读全帖 |
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l***d
发帖数: 1828 | 4 生理学或医学
Brian J. Druker 美国奥勒冈州波特兰市奥勒冈健康暨科学大学 (Oregon Health
Science University)医学教授、JELD-WEN血癌研究教授及奈特癌症研究所(OHSU
Knight Cancer Institute)主任、同时也是霍尔休斯医学研究所(Howard Hughes
Medical Institute)研究人员
Nicholas B. Lydon 美国怀俄明州杰克森洞(Jackson Hole, WY)Granite ***a, LLC
创办人；美国加州圣地牙哥AnaptysBio共同创办人兼总监；及美国麻州剑桥Blueprint
Medicines共同创办人兼总监
Charles L. Sawyers 美国纽约州纽约市Memorial Sloan-Kettering癌症中心人类肿
瘤学及病因Marie-Josee and Henry R. Kravis教授、同时也是霍尔休斯医学研究所(
Howard Hughes Medical Institute)研究人员
获奖成就：他们发展出***性慢性骨髓性白血病治疗药物im... 阅读全帖 |
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b*****h
发帖数: 25 | 5 【 以下文字转载自 Mathematics 讨论区,原文如下 】
发信人: benhigh (benhigh), 信区: Mathematics
标 题: 偶看不懂这道linear programming题目叫俺干吗？
发信站: Unknown Space - 未名空间 (Wed Oct 13 16:01:16 2004) WWW-POST
题目如下：
The purpose of this problem is to show that solving linear programming
problems is no harder than solving systems of linear inequalities.
Suppose that we are given a subroutine which, given a system of linear
inequality constraints, either produces a solution or decides that no solution
exists. Construct a simple algori |
|
a*1
发帖数: 120 | 6 另外中国教育的不均匀更多体现在初等教育不均匀的问题上,你如果把中国教育的不公
平之处全列出
来，相信现行的高考制度并不是最严重的。
你可以参见WU XIAOGANG关于中国教育的研究
Wu, Xiaogang and Donald J. Treiman. 2007. “Inequality and Equality under
Chinese Socialism: The Hukou System and Intergenerational Occupational
Mobility.” American Journal of Sociology 113(2):415-45.
Wu, Xiaogang and Yu Xie. 2003. “Does the Market Pay Off? Earnings
Inequality and Returns to Education in Urban China.” American
Sociological Review 68:425-442. |
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y*****y
发帖数: 1208 | 7 A good friend of mine forwarded this and asked for support. It's about Asian
American students are being discriminated against and held at higher
standards than other ethnic groups in college admissions.
====================================================================
A Call to End Racial Preference in College and University Admissions
====================================================================
Dear Friends and Asian Parents,
I am writing to you regarding the serious violation of eq... 阅读全帖 |
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n******r
发帖数: 3 | 8
It is not that hard as you thought, but you may need Cauchy-Schwarz
inequality.
a <= E|X| = E{|X|*I[X=sa]} [where I is indicator function]
<= sa + sqrt(E{|X|^2}*E{I[X>=sa]}) [use C-S inequality and I^2=I]
= sa + sqrt(1*P(X>=sa))
So P(X>=sa) >= (1-s)^2*a^2. # |
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n*******l
发帖数: 2911 | 9 f(x) = |x|^r is convex for r>=1.
So f( a/2 + b/2 ) < = f(a)/2 + f(b)/2.
Simplify the above inequality, we can get the desired inequality. |
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s***t
发帖数: 13743 | 10 You can just try to solve the inequality
[(A+7)*(B-3)]/[(C-D)*(E^2+1)]>0
But you need to load some extra package to solve inequalities.
繁
夜
当 |
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n*******l
发帖数: 2911 | 11 Dynkin's inequality is not correct since obviously
the powers are not balanced. But it is not fatal.
By Holder's inequality, we can prove
f(n) = ((a^n+b^n)/2)^(1/n)
is an increasing function of n>1 for a>0, b>0.
So
((a^n+b^n)/2)^(1/n)>= ( (a^2+b^2)/2 )^(1/2) >=(a+b)/2. |
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s******h
发帖数: 539 | 12 Excellent method for the dude on the 2nd floor, what I want to comment is
how I might come up with this method:
1. In scalar version,
(\sum_i=1^n 1)^2
=[\sum_i=1^n \sqrt{a_i}*(1/\sqrt(a_i))]^2
<=(\sum_i=1^n a_i^2)(\sum_i=1^n 1/a_i^2)
As the author mentioned, it's Cauchy-Schwartz Inequality;
2. Remember how we prove Cauchy-Schwartz Inequality for different
versions, one common method is to consider 2nd moment as follows
\sum_{i=1}^n(\sqrt{a_i}+1/\sqrt{a_i}*x)^2>=0, for all x\in |
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s******h
发帖数: 539 | 13 Consider f(x) = \log( 1 + \exp{x} )
then f(x) is a convex function in R,
by Jensen's Inequality,
http://en.wikipedia.org/wiki/Jensen's_inequality#Finite_form
f( \sum_{i=1}^n \log(x_i) / n) <= \sum_{i=1}^n f(\log x_i) /n
i.e. log( 1 + {\prod_{i=1}^n x_i }^{1/n} ) <= \sum_{i=1}^n log(1 +x_i) /n.
This completes the proof.
Just say that this is true by Jensen's Inequality. |
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l****y
发帖数: 92 | 14 let f(x) be a function defined for all x from an interval (c,d) containing a
point x0. suppose that f(x) is continuous at the point x0, and f(x0)/=0 (
does not equal to 0), which of the following is true?
a) there exists a neighborhood (x0-a,x0+a), a>0, of the point x0 at whose
all points fulfill the inequality |f(x)|>f(x0)/2
b) for each a>0, the inequality |f(x)|>a*f(x0) is true for all x belongs to
(x0-a,x0+a)
c) for each number M strictly greater than |f(x0)|, there exists a
neighborhood N=(x |
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c*****a
发帖数: 49 | 15 我在wiki上看到了这个不等式，但是老板说要引用参考书。不知道那本经典的教科书上
有讲。望大虾们指点一本。
多谢！ |
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c*******h
发帖数: 1096 | 16 the special thing comes from the very beginning where you assume
|Ay| \leq \|A\|*|y|
this inequality may not be true. For example, define the norm of
a matrix A as max_{ij}|a_{ij}|, and let A be the 2-by-2 matrix of
all ones. Also consider the vector as a special case of matrix,
and let y = [1 2]'. Then A has norm 1, y has norm 2. However, Ay
has norm 3.
your assumed inequality is true iff the norm defined for matrix and
that defined for vector are compatible. when people talk about
operators, t |
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f********t
发帖数: 14 | 17 一个貌似简单的问题，觉得对但又不敢确定，请高手指教。
U（x,y） is a continuously differentiable function of (x,y).
For three fixed values y1, y2 and x0,
a*U(x0,y2)+(1-a)*U(x0,y1)>U(x0,a*y2+(1-a)*y1),
where 0=
Add a small term k*a*(1-a) to x0, for k small enough, I claim the inequality
is still true, as follows,
a*U(x0+k*a*(1-a),y2)+(1-a)*U(x0+k*a*(1-a),y1)>U(x0,a*y2+(1-a)*y1).
Let f(a)=a*U(x0+k*a*(1-a),y2)+(1-a)*U(x0+k*a*(1-a),y1)-U(x0,a*y2+(1-a)*y1),
the diff |
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f********t
发帖数: 14 | 18 Thank you so much!
I see your points.
If I modify the small term, and let it be any positive number, so the desired inequality
is
a*U(x0+emisilon,y2)+(1-a)*U(x0+emisilon,y1)>U(x0,a*y2+(1-a)y1). Do you think
if we assume U(x,y) is absolutely continuous, is the inequality true? |
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z***c
发帖数: 102 | 19 Here is a geometrical explanation. Let u and v be vectors, |u| denote vector
norm, and the inner product. Cauchy's inequality
\le |u| |v|
is equivalent to
/|v| \le |u|.
The left hand side has a geometric meaning: it is the projection of u onto
the direction of v. Hence Cauchy's inequality simply means that the
projection of a vector has shorter or equal length than the vector itself.
This can be easily proved using a right triangle.
Now, this proof actually inspires the proof giv... 阅读全帖 |
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A***C
发帖数: 143 | 20 Starting from Cauchy inequality, 有简单的证法吗？
我从Cauchy inequality开始的证明还是很复杂。 |
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r**q
发帖数: 251 | 21 他老爹alan guth 好像没得诺贝尔物理奖吧?
Larry Guth is professor of mathematics at the Courant Institute.
Guth received his Ph.D. in 2005 from the Massachusetts Institute of
Technology under the supervision of Tomasz Mrowka.[1] He was invited speaker
at the International Congress of Mathematicians in India in 2010, where he
spoke about systolic geometry.[2][3] In his research, Guth has strengthened
Gromov's systolic inequality for essential manifolds[4] and found a solution
to the Erdős distinct distances... 阅读全帖 |
|
g****t
发帖数: 31659 | 22 搭车问一下:网上有了去年大会的论文集了么?
他老爹alan guth 好像没得诺贝尔物理奖吧?
Larry Guth is professor of mathematics at the Courant Institute.
Guth received his Ph.D. in 2005 from the Massachusetts Institute of
Technology under the supervision of Tomasz Mrowka.[1] He was invited speaker
at the International Congress of Mathematicians in India in 2010, where he
spoke about systolic geometry.[2][3] In his research, Guth has strengthened
Gromov's systolic inequality for essential manifolds[4] and found a solution
to the Erd... 阅读全帖 |
|
b*****e
发帖数: 88 | 23 Thanks, you are right.
I have been able to show that if b>2*c, then the inequality holds. Also
notice that as 'a' goes to infinity, b(a) has to go to infinity as well. So,
as 'a' is large, the inequality holds.
functions |
|
f***r
发帖数: 1126 | 24 suppose f is monotonic.
Suppose f(0)=c.
(1) choose x=0. f(f(y))-c=f(*)>=f(0)=c
therefore f(f(y))>=2c for all y
(2)choose x=c
f(c/2 +f(c)/2+y)=2c-f(c)+f(f(y))=2c-f(f(0))+f(f(y))<=f(f(y))
f is monotonic, so
c/2+f(c)/2+y<=f(y) for all y.
(3) choose y=0
f(x/2+f(x)/2)+f(x)=2x+f(c). Using the inequality of (2) twice and obtain
2x+f(c)>=f(x+c/4+f(c)/4)+x+c/2+f(c)/2
>=x+c/4+f(c)/4+c/2+f(c)/2+x+c/2+f(c)/2
>=2x+f(c)+5c/4+f(c)/4
>=2x+f(c)
Therefore c=f(c)=0 and all the inequalities sho... 阅读全帖 |
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o*******w
发帖数: 349 | 25 Picard iteration 不行了，因为只能证明局部uniqueness。当然在确定情形下，反复
用多次也可以将唯一性extend到大区间（多个小区间连起来就行）。但用于我这种带随
机的情形看来不大行，因为只有第一个区间有初始点。
于是又找了一个方法，用Gronwall‘s inequality来证明解dependent continuously
on 初始条件。
Gronwall‘s inequality 方法不需要小区间的限制，而需要全局 Lipschitz
continuous，这个我满足。
下一步就是要看看能不能用于随机情况。
Ref:
http://www.math.colostate.edu/~pauld/M345/Some%20theory.pdf |
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s******r
发帖数: 9 | 26 建立图G(V,E)如下:
V={v1,v2,...,v9}.
E={(v1,v2) | 如果v1,v2握过手}
这样,|E|=(1*2+2*4+4*5+2*6)/2=21
利用定理:如果图G(V,E)不存在三角形,则 |E|<=n*n/4 (n为点数)
因为 21>9*9/4, 所以存在三角形 (v_i,v_j,v_k).
于是,v_i,v_j,v_k 三人互相握过手.
定理的证明(Hint): Observe that for each edge (x,y), there
exist a
inequality:
deg(x)+deg(y)<=n,
add all these inequalities together. |
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s**********p
发帖数: 17 | 27 The parametric down conversion crystal is BBO(beta-Barium Borate). The
entangled state is contructed according to one of the four Bell-EPR states,
and the violation of Bell inequality is measured by the CHSH inequality. The
quantum key distribution rate is 10 bits/s. They send a synchronous signal
from another optical channel to gate the coincidence measurement.
The transmission rate is 70% with 3000 pairs of entangled photons left for
spacelike Eves. :) Is it because the telescope they built, t |
|
s**a
发帖数: 8648 | 28 The new Center for the Study of Poverty and Inequality at Stanford
University will be filling two postdoctoral positions for the 2007-08
academic year (and possibly beyond). The announcements are attached. Could
you please let your students know about the positions and, if possible,
post the announcements? Much thanks!
David B. Grusky
Director, Center for the Study of Poverty & Inequality
Professor, Dept. of Sociology, Stanford University
450 Serra Mall
Bldg. 120, McClatchy Hall
Stanford Univ |
|
s**a
发帖数: 8648 | 29 I know it is probably not suitable, but what the hell...
Job Ad:
http://www.u.arizona.edu/~breiger/advertisements.htm
University of Arizona. The Department of Sociology invites
applications at the senior tenured level (associate or full
professor) to join our faculty in Fall 2008, contingent upon
availability of position funding. We welcome applicants in all areas
of specialization. Areas of interest include social inequality,
including race, ethnic, and gender inequality, and social
organizatio |
|
s**a
发帖数: 8648 | 30 具体情况见附件。
The Yale Sociology Department's Center for Research on Inequalities and the
Life Course (CIQLE) is looking for a new postdoc starting next fall. Please
find the attached ad, and feel free to apply or circulate/add it to your
mailing lists.
Thank you,
Chelsea Rhodes
Senior Administrative Assistant
Center for Research on Inequalities and the Life Course (CIQLE)
Department of Sociology
Yale University
Tel.: (203) 432-9587
Fax: (203) 436-4952 |
|
g******n
发帖数: 339 | 31 来自主题: Statistics版 - 问个证明题 sorry, I wasn't very careful.
The inequality you try to prove is essentially E(X)*E(1/X)>=1, since X and Y
are IID.
It seems that if the support of X includes 0, then you would have to define
E(1/X) carefully, as E(1/X) could be infinity. In special cases when the
support of X is positive, i.e, when X is defined (or a subset) on (0,+
infinity), the proof is simply Jensen's inequality:
Jensen's: if g(.) is convex and defined on the support of X, then E[g(X)]>=g
(E(X))
let g(w) be 1/w (w in (0, +i |
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c******r
发帖数: 300 | 32 Imagine there is a random variable J such that var(J) = A
then the lefthand side is Cov(x'J, y'J)^2
while the righthand side is Var(x'J)Var(y'J)
the inequality is then the Cauchy-Schwarz inequality. |
|
L****o
发帖数: 1 | 33 民科’s guess:
Since X>0, E(X) is always defined. Two cases to be considered.
(1)E(X)0, ln(X) is defined and hence Eln(X)<00 because of E(X)<
oo. Then by Jensen inequality, we see that E(X/Y)=Eexp{ln(X/Y)}>=exp{Eln(X/Y
)}=exp{Eln(X)-ElnY}=0, where the last equality is obtained since lnX and LnY
have the same marginal distribution and their first moments are finite.
(2)E(X)=oo. Since X>0, we can always find a large positive integer m such
that E{X^(1/m)}阅读全帖 |
|
s*********e
发帖数: 884 | 34 2.3 Administration and Financing
This section examines the state and trends in administration and financing
in schools in rural China. Fiscal decentralization has been a key feature of
China’s economic reform, leading to the devolution of responsibilities
over both revenue collection and public expenditures to lower levels of
government—the province, county, township, and village. While a
decentralized system improves incentives for local governments to generate
revenues and to be responsive to ... 阅读全帖 |
|
s***r
发帖数: 1121 | 35 http://www.ruanyifeng.com/blog/2007/08/remarks_of_bill_gates_in
by 阮一峰
In line with the promise of this age, I want to exhort each of the graduates
here to take on an issue - a complex problem, a deep inequity, and become a
specialist on it. If you make it the focus of your career, that would be
phenomenal. But you don’t have to do that to make an impact. For a few
hours every week, you can use the growing power of the Internet to get
informed, find others with the same interests, see the barrie... 阅读全帖 |
|
t**g
发帖数: 784 | 36 http://www.nytimes.com/2013/12/29/us/a-rare-elected-voice-for-s
By KIRK JOHNSON
SEATTLE — People are used to liberals running things around here. But
nobody reckoned with Kshama Sawant. Ms. Sawant, a 41-year-old economics
teacher and immigrant from India, took a left at liberal and then kept on
going — all the way to socialism.
When she takes a seat on Seattle’s nine-member City Council on Jan. 1,
representing the Socialist Alternative Party, she will become one of the few
elected socialists in ... 阅读全帖 |
|
B********4
发帖数: 7156 | 37 这个问题我也迷糊了很久，查了不少资料，但还不是100%有把握。希望学统计的来指正
一下。
p-value是说在零假设（H0)之下出现看到该情况或者更极端情况的概率，也就是假设硬
币是fair的，抛6次出现5个head或者6个head的概率。因为我们考虑对称性，所以还要
考虑到1个head或者0个head的情况。楼主的p-value计算是对的。
significance level α只是预先设定的一个判定p-value的阈值（即多小的概率算小概
率事件），如果p<=α，我们认为零假设不对(因为在H0之下居然观察到了一个小概率事
件，肯定假设H0有问题）。反之，如果p>α,我们接受零假设H0。
根据wikipedia "given the availability of a hypothesis testing procedure that
can test the null hypothesis θ = θ0 against the alternative that θ ≠ θ
0 for any value of θ0, then a confidence interval with... 阅读全帖 |
|
B********4
发帖数: 7156 | 38 这个问题我也迷糊了很久，查了不少资料，但还不是100%有把握。希望学统计的来指正
一下。
p-value是说在零假设（H0)之下出现看到该情况或者更极端情况的概率，也就是假设硬
币是fair的，抛6次出现5个head或者6个head的概率。因为我们考虑对称性，所以还要
考虑到1个head或者0个head的情况。楼主的p-value计算是对的。
significance level α只是预先设定的一个判定p-value的阈值（即多小的概率算小概
率事件），如果p<=α，我们认为零假设不对(因为在H0之下居然观察到了一个小概率事
件，肯定假设H0有问题）。反之，如果p>α,我们接受零假设H0。
根据wikipedia "given the availability of a hypothesis testing procedure that
can test the null hypothesis θ = θ0 against the alternative that θ ≠ θ
0 for any value of θ0, then a confidence interval with... 阅读全帖 |
|
m****e
发帖数: 1956 | 39 是对的，但是这个markov inequality也适用于非LCB啊。
如果E{x}=平均成功率，a=5倍成功率=5E{x}=something good
P{X>=a} <= E{x}/a=1/5=只有20%的人能得到5倍于平均成功率
注意上面没有用到LCB，是LCB independent的，markov inequality对所有人都是一样
的。 |
|
o******d
发帖数: 743 | 40 * The Talk Of The Town (10/12/2010)
(South China Morning Post) Barry Sautman and Yan Hairong October 12,
2010.
In non-peace related fields, there are Nobel Prizes and, somewhat
less famously, "Ig Nobel Prizes". A group of scientists presents the latter
annually, as a joke, but also to make a point about undeserving activity in
their fields. One of the winners of this year's Nobel prize for physics had,
several years back, also received an Ig Nobel prize.
The award of ... 阅读全帖 |
|
v******s
发帖数: 272 | 41 http://www.nytimes.com/2010/11/18/world/asia/18li.html?_r=1&hp
China’s Censorship Backfires in ‘Li Gang’ Case
BAODING, China — One night in late October, a college student named Chen
Xiaofeng was in-line skating with a friend on the grounds of Hebei
University in central China. They were gliding past the campus grocery
when a Volkswagen sedan raced down a narrow lane and struck them head-
on.
The impact sent Ms. Chen flying and broke the other woman’s leg. The 22-
year-old driver, who was intoxi... 阅读全帖 |
|
a*****y
发帖数: 33185 | 42 【 以下文字转载自 FaJia 俱乐部 】
发信人: arthury (非正常人类研究中心主任), 信区: FaJia
标 题: 《王权论》王权政治的理论基石 (转载)
发信站: BBS 未名空间站 (Sun Jan 2 21:04:18 2011, 美东)
【 以下文字转载自 Wisdom 讨论区 】
发信人: arthury (非正常人类研究中心主任), 信区: Wisdom
标 题: 《王权论》王权政治的理论基石
发信站: BBS 未名空间站 (Tue Nov 30 01:45:13 2010, 美东)
引言
http://book.sina.com.cn 2009年08月11日10:36 新浪读书
就像植物生长需要根茎，大厦建成需要地基一样，一种思想学说的建立，也需要有它的
理论基石，换言之，即是思想学说得以建立的基本原则。尽管韩非子的思想学说从没有
提及他的理论基石——在那样的时代和那样的语境习惯下也不可能有这样的论述，但他
的观点有着一以贯之的严密逻辑。我们可以通过梳理他的学说，找到他的思想认识起点
，探索这些基本原则的潜在内容，逐渐揭示和勾勒出韩非子政治思想的理论轮... 阅读全帖 |
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c*********2
发帖数: 3402 | 43 http://behindthewall.msnbc.msn.com/_news/2012/04/11/11141788-ho
Stringer/China / Reuters
China's former Chongqing Municipality Communist Party Secretary Bo Xilai and
his wife Gu Kailai pose in this January 17, 2007 file photo.
By Eric Baculinao and Bo Gu, NBC News
BEIJING – The political shock waves set off from within a U.S. diplomatic
compound by a disgruntled ex-cop in the southwestern city of Chengdu have
culminated into what may well be China’s biggest political scandal in years
.
Already ... 阅读全帖 |
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s**********t
发帖数: 1846 | 44 favored Red book:
Obama's America: Unmaking the American Dream,
Fool Me Twice: Obama's Shocking Plans for the Next Four Years Exposed
Paul Ryan favourite Ayn Rand's Atlas Shrugged.
The Amateur: Barack Obama in white house
Favored Blue book
A People's History of the United States
The Price of Inequality: How Today's Divided Society Endangers Our Future.
Dreams From My Father
The Audacity of Hope.
Or another exaplanation:
liberals don't read
Blacks can't affort to read
Hispanic can't read
single m... 阅读全帖 |
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H****g
发帖数: 14447 | 45 【 以下文字转载自 Military 讨论区 】
发信人: Herzog (singularity), 信区: Military
标 题: Re: Clay Christensen谈人生的意义在于为人民服务
发信站: BBS 未名空间站 (Tue Nov 6 18:05:43 2012, 美东)
Progress and poverty, by Henry George
http://files.libertyfund.org/files/328/George_0777.mobi
Henry George和Karl Marx基本算是同代人了，面对的社会现象类似，得出的结论也很
接近，比如说wage slave，inequality，比如说Henry George在上面这本书的开始就提
出自己的假说，认为工资来自于工人的劳动，而不是资本。这就从根本上否定了资本家
养活工人。马克思分析的更进一步，认为说资本家利润来自于剩余价值，而剩余价值是
劳动价值减去工资的部分，资本主义的生产其实就是剩余价值的生产。从批判角度说，
马克思的批判就更精确一些。
Henry George之所以在西方li... 阅读全帖 |
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I********l
发帖数: 8702 | 46 【 以下文字转载自 Military 讨论区 】
发信人: Irrational (Herzog), 信区: Military
标 题: 马列课应当保留，现有教材应当废除
发信站: BBS 未名空间站 (Thu Jul 4 23:08:05 2013, 美东)
国内马列教材基本是由周天勇这样压根不信共产主义的党校叫兽编出来的，所以的确应
该取消现有的马列教材，改用全新的马列教材。
比如介绍马克思主义的通俗读物，可采用Chris Harman的How Marxism Works；Terry
Eagleton的Why Marx was Right；
介绍资本论的，可采用David Harvey的资本论导读，资本之谜；
介绍资本主义发展史，可采用Eric Hobsbawm的帝国三部曲；
介绍资本主义舆论控制，可采用Chomsky的Media Control；
介绍资本主义精英统治的，可采用C. W. Mills所著的The Power Elite；
介绍马克思主义经济学，可采用Oxford出版的那本Understanding Capitalism；
介绍全球化的书，可采用诺奖得主斯蒂格利... 阅读全帖 |
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M***O
发帖数: 3718 | 47 http://www.tealeafnation.com/2013/04/why-time-is-running-out-on
In recent years, issues about China’s pension system have repeatedly hit a
public nerve. Among the hot topics consistently reappearing on the front
pages of Chinese papers, the social pension perhaps has the most direct
influence on people’s lives. Yet convoluted procedures and a lack of
transparency make the institution hard to decipher. From time to time,
officials, scholars and citizens have debated whether there is a major
crisi... 阅读全帖 |
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c***s
发帖数: 70028 | 48 房价在金融风暴打击後没有股市回升的快，使大批中产阶级损失惨重。图为佛州奥兰多一名房屋仲介带客人看房。（美联社）
房价在金融风暴打击後没有股市回升的快，使大批中产阶级损失惨重。图为迈阿密一栋待售房屋。（美联社）
据密西根大学社会研究中心最新出炉研究调查显示，走过金融危机，美国家庭财富不仅没有“重新分配”，反而使全美最富有家庭，与一般中产家庭的财富差距，从2003年的相差13倍，加速恶化到2013年的24倍。
这项由密大社会研究中心助理教授费佛尔(Fabian Pfeffer)提出的报告，在史丹坦贫困与不平等研究中心(Stanford Center for the Study of Poverty and Inequality)网站发表。
费佛尔指出，从2003年到2013年期间，美国经历金融风暴，所有家庭不管贫富，都因此遭到不同程度的重挫，虽然富有家庭在这段时期损失大量财富，但中低阶层家庭却损失更多。
★2003年仅13倍
这份报告指出，2003年时，美国最富有5%家庭的财富，是一般中产家庭的13倍，而到了2013年，5%的富有家庭财富，却比一般中产家庭足足高出24倍。
费佛尔与研究中心... 阅读全帖 |
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c******a
发帖数: 4400 | 49 climate extremes and inequality
IPCC did not bluff |
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e****i
发帖数: 2152 | 50 【 以下文字转载自 Military 讨论区 】
发信人: erkuai (三天不上bbs,赶得上刘少奇), 信区: Military
标 题: On the Jews and Their Lies, 1543
发信站: BBS 未名空间站 (Wed Jan 12 23:21:23 2011, 美东)
by Martin Luther (1483-1546)
Translated by Martin H. Bertram
copyright © 1971 Fortress Press & Augsburg Fortress - On the Jews and
Their Lies is from Luther’s Works Volume 47. Augsburg Fortress is the
publishing ministry of the Evangelical Lutheran Church in America.
Funded through sales revenue, Augsburg Fortress is called to provide
produ... 阅读全帖 |
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